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2 years ago

5

10-20. There are 12 girls and 24 boys in Mrs. Andrew's gym class. To play a

2 answers:

Anon25 [30]2 years ago

8 0

Answer:

12

Step-by-step explanation:

24÷2=12 wich simple mean that 12 is gonna make the equal team

Neporo4naja [7]2 years ago

3 0

Answer:

12 boys and 6 girls in each team

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Please help me and pls do both

Nana76 [90]

Answer:

7/36

Step-by-step explanation:

find the LCD write all the numerators above the least common denominator

LCD is 36

4 +3 /36 =7/36

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2 years ago

Charlotte has two job offers as a car sales person. The first job will pay her $600 a month plus 2% on the price of her car sale

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$40,000
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2 years ago

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melisa1 [442]

30 centimeters cubic centimeters

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2 years ago

Which expression is equal to 5^4 ⋅ 5^8?

alex41 [277]

It should be A. You would keep the 5, and the exponent should be 4+8, which is 12.

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3 years ago

Read 2 more answers

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago