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2 years ago

10-20. There are 12 girls and 24 boys in Mrs. Andrew's gym class. To play a

Mathematics

2 answers:

Anon25 [30]2 years ago

8 0

Answer:

Step-by-step explanation:

24÷2=12 wich simple mean that 12 is gonna make the equal team

Neporo4naja [7]2 years ago

3 0

Answer:

12 boys and 6 girls in each team

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Can someone Please help me?

aalyn [17]

Answer: The constant of proportionality is 3.5, so your answer would be B.

7 0

3 years ago

Graph the linear equation find three points that solve the equation, then plot on the graph y=-x+2

Maslowich

Step-by-step explanation: x= 2-y then plug that in for x so y= 2-y+2;

y=4-y; -4y=-y; y=-1/4

4 0

3 years ago

Rectangle A is a scale drawing of Rectangle B and has 25% of its area. If rectangle A has side lengths of 4 cm and 5 cm , what a

SpyIntel [72]

Answer:

8 cm and 10 cm

Step-by-step explanation:

Hello, <em> </em>I can help you with this.

Step 1

According to the question there are two rectangles A and B,

Rectangle A is a scale drawing of Rectangle B and has 25% of its area

in other words

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\$

Step 2

Let

Rectangle A

length (1)= 4 cm

length (2)= 5 cm

$Area_{A}=4\ cm * 5\ cm\\Area_{A}=20\ cm^{2}$

put this value into equation 1

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\\\20\ cm^{2} =0.25*Area_{B} \\divide\ each\ side\ by\ 0.25\\\frac{20\ cm^{2} }{0.25}=\frac{0.25}{0.25}*Area_{B}\\ Area_{B}=80\ cm^{2}$

Now, we know the area of rectangle B, to know its length we need to formule other equation

Step 3

$Area_{B}=80\ cm^{2}\\length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\$

the ratio between the lengths must be constant, so the ratio of A must be equal to ratio in B, then

$\frac{length(1A)}{length(2A)}=\frac{length(1B)}{length(2B)} \\\\\\frac{4}{5}= \frac{length(1B)}{length(2B)}\\0.8=\frac{length(1B)}{length(2B)}\\length(1B)=0.8*length(2B) (Equation 3)$

Step three

using Eq 1 and Eq 2 find the lengths

put the value of length(1B) into equation (2)

$length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\\(0.8*length(2B)) (*length (2B)=80\ cm^{2} \\\\0.8*(length (2B))^{2} =80\ cm^{2}\\(length (2B))^{2} =\frac{80\ cm^{2}}{0.8} \\(length (2B))^{2}=100\\\sqrt{(length (2B))^{2}}=\sqrt{100\ cm^{2}} \\ length (2B)=10\ cm$

Now, put the value of length(2B) into equation 3 to know length (1B)

$length(1B)=0.8*length(2B)\\length(1B)=0.8*10\ cm\\length(1B)=8 cm$

I really hope this helps you, have a great day.

6 0

3 years ago

A sports team played 100 games last season. Did this team win at least half of the games it played last season? (1) The team won

Lelechka [254]

Answer:

Insufficient data.

Step-by-step explanation:

Given,

Total number of games = 100,

(1) The team won 60% of its first 65 games last season.

So, the number of winning games in 65 games = 60% of 65

$=\frac{60\times 65}{100}$

$=13\times 3 = 39$

But we do not know about the data for last 35 games,

Thus, the data is insufficient.

(2) The team won 60% of its last 65 games last season.

So, the number of winning games in last 65 games = 60% of 65 =39,

Thus, the total winning games = 45 + 45 = 90,

But we do not know about the data for first 35 games,

Thus, the data is insufficient.

When we combined both (1) and (2) statements,

we found that the maximum number of games won by the team = 39 + 39 = 78,

But there is a overlap of 30 games,

i.e. an unknown number will be subtract from 78 to find the exact number of winning games.

Hence, even after combining statements (1) and (2),

The data is insufficient.

6 0

3 years ago

What's the best app for graphing answers like domain y intercept all those things

denis23 [38]

Answer: it’s not an app but desmos graphing calculator works for me

Step-by-step explanation:

5 0

3 years ago