What is the solution to the linear equation 6k+10.5=3k+12

Albert wants to buys some pens. He is comparing 4 different packs of pens. The number of pens in each pack and the cost of the p

Musya8 [376]

Answer:

There are 2 red pens in each pack

There are 3 blue pens in each pack

Step-by-step explanation:

270=2*3^{3} *5

180=2^{2}*3^{2}*5

<u>Find the Greatest Common Factor (GCF)</u>

The GCF is equal to------> 2*3^{2}*5=90

the greatest number of packs she can make is 90

Find the number of red pens in each pack 180/90=2 red pens

Divide the total number of red pens by the total number of packs

Find the number of blue pens in each pack 270/90=3 blue pens

Divide the total number of blue pens by the total number of packs

6 0

3 years ago

Divide 35 by 12. Input your answer as a reduced fraction

Mars2501 [29]

Answer: =2 2 /3

Step-by-step explanation: =32÷412÷4=83

Converting to a mixed number using long division with remainders for 8 ÷ 3.

8÷3=2R2

Therefore:

83=223

3 0

3 years ago

Can someone help me with this question

d1i1m1o1n [39]

Answer:

Angle 1 and angle 4 are congruent because all vertical angles are congruent. Angle 1 and angle 5 are congruent because corresponding angles are congruent. Idk the rest.

Step-by-step explanation:

7 0

3 years ago

Timothy creates a game in which the player rolls 4 dice. What is the probability in this game of having exactly two dice or more

devlian [24]

Answer:

B. 0.132

Step-by-step explanation:

For each time the dice is thrown, there are only two possible outcomes. Either it lands on a five, or it does not. The probability of a throw landing on a five is independent of other throws. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Timothy creates a game in which the player rolls 4 dice.

This means that $n = 4$

The dice can land in 6 numbers, one of which is 5.

This means that $p = \frac{1}{6}$

What is the probability in this game of having exactly two dice or more land on a five?

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(\frac{1}{6})^{2}.(\frac{5}{6})^{2} = 0.116$

$P(X = 3) = C_{4,2}.(\frac{1}{6})^{3}.(\frac{5}{6})^{1} = 0.015$

$P(X = 4) = C_{4,4}.(\frac{1}{6})^{4}.(\frac{5}{6})^{0} = 0.001$

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.116 + 0.015 + 0.001 = 0.132$

So the correct answer is:

B. 0.132

8 0

3 years ago

Suppose you have to use right-triangle trigonometry to find the apothem of a regular polygon. Which is greater, the apothem or t

asambeis [7]

The apothem represents one side of the right triangle to be solved. Specifically, it represents the height of the triangle.
The radius of the polygon represents the hypotenuse of the right triangle that is going to be solved.
Therefore, we can infer that the radius of the polygon is greater than the apothem because the hypotenuse is greater than all sides of a triangle.
Answer:
the radius of the polygon is greater

8 0

3 years ago