2 years ago

2x(3+4)to the 2nd power

Mathematics

1 answer:

kotykmax [81]2 years ago

6 0

Answer:

196

Step-by-step explanation:

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Write an expression for the area of a triangle with a height of 2x^2 units and a base of 5x^2+4x units

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The area of the triangle is $5x^4 + 4x^3$ square units

Step-by-step explanation:

Given

Shape: Triangle

$Height = 2x^2$

$Base = 5x^2+4x$

Required

The area of the triangle

The area of a triangle is calculated as thus;

$Area = \frac{1}{2}(base)(height)$

By substituting $Height = 2x^2$ and $Base = 5x^2+4x$ ; This gives

$Area = \frac{1}{2}(5x^2 + 4x)(2x^2)$

$Area = \frac{(5x^2 + 4x)(2x^2)}{2}$

$Area = (5x^2 + 4x)(x^2)$

Open Bracket

$Area = 5x^2 * x^2 + 4x * x^2$

$Area = 5x^4 + 4x^3$

Hence, the area of the triangle is $5x^4 + 4x^3$ square units

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2x(3+4)to the 2nd power​

2x(3+4)to the 2nd power