Relative extrema occur where the derivative is zero (at least for your polynomial function).
So taking the derivative we get
<span>20<span>x3</span>−3<span>x2</span>+6=0
</span><span>
This is a 3rd degree equation, now if we are working with complex numbers this equation is guaranteed to have 3 solutions by the fundamental theorem of algebra. But the number of real roots are 1 which can be found out by using Descartes' rule of signs. So the maximum number of relative extrema are 1.</span>
D. (y-3)
I'm assuming that they want you to find the factors of the quadratic expression, which are (y-5)(y-3). (y-5) isn't up there, so (y-3) is the only solution that's really possible.
(-1.5,3) Y=3 which is up 3 and a horizontal line and 2x+y=0 can be written as y=-2x so in order to get -1.5 you have to make y=3 cause y=3 and when you do that it should look like 3/-2=-2/-2x so x=-1.5
3.643 x 10^3
move the decimal in between the first and second number
However many times you move the decimal, that is you exponent.
