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masya89 [10]
3 years ago
5

All my question are about math and this test determines my high school classes help if you can please

Mathematics
1 answer:
Mashcka [7]3 years ago
3 0

Answer:

y = x+2

Step-by-step explanation:

When x = 0, y =2

So, y = 0 + m

2 = 0 + m

2 = m

When x = 1, y =3

y = x + m

3 = x + 2

-2        -2

1 = x

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What is x in x - 4 (x - 3) + 7 = 6 - (x - 4)
WINSTONCH [101]
-1 use mathpapa it will give you the answar

6 0
3 years ago
Two families are sharing the cost of vacation home for one week. The cost to rent the home is $3,513 plus a $351.30 deposit. Wha
Natali [406]

The answer is $1932.15

3,513+351.30=3864.30

3864.30÷2=1932.15

Hope this helps!

6 0
4 years ago
Read 2 more answers
Suppose babies born in a large hospital have a mean weight of 3242 grams, and a standard deviation of 446 grams. If 107 babies a
777dan777 [17]

Answer:

64.76% probability that the mean weight of the sample babies would differ from the population mean by less than 40 grams

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 3242, \sigma = 446, n = 107, s = \frac{446}{\sqrt{107}} = 43.12

What is the probability that the mean weight of the sample babies would differ from the population mean by less than 40 grams

This is the pvalue of Z when X = 3242 + 40 = 3282 subtracted by the pvalue of Z when 3242 - 40 = 3202

X = 3282

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3282 - 3242}{43.12}

Z = 0.93

Z = 0.93 has a pvalue of 0.8238.

X = 3202

Z = \frac{X - \mu}{s}

Z = \frac{3202 - 3242}{43.12}

Z = -0.93

Z = -0.93 has a pvalue of 0.1762

0.8238 - 0.1762 = 0.6476

64.76% probability that the mean weight of the sample babies would differ from the population mean by less than 40 grams

5 0
3 years ago
Simplify to create an equivalent expression.<br> 2 – 4(5p + 1)
Ganezh [65]

Answer:

A. -20p - 2

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

2 - 4(5p + 1)

<u>Step 2: Simplify</u>

  1. Distribute -4:                    2 - 20p - 4
  2. Combine like terms:        -20p - 2
6 0
3 years ago
Read 2 more answers
During a basketball game, Bari scored 28 points. During the same game, Denay scored
Elza [17]

Answer:

28 points

Step-by-step explanation:

If they scored the same amount then Denay would have scored 28 as well

Hope that helps

6 0
3 years ago
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