All categories

2 years ago

What is the value of f(g(-3)?

Mathematics

1 answer:

Natalija [7]2 years ago

8 0

Answer:

f(x) + g(x) = (-2x + 8)+ 3x

f(x) + g(x) = -2x + 8 + 3x Combine like terms.

f(x) + g(x) = x + 8

f(x) + g(x) = (f+g)(x) = x + 8

(f + g)(-1) = -1 + 8

(f + g)(-1) = 7

Step-by-step explanation:

You might be interested in

HI HOW ARE YOU MY DUDE!!!

vagabundo [1.1K]

Answer:

I'm fine how are you?

stay safe

7 0

3 years ago

Read 2 more answers

A direct variation includes the points (4,16) and (1,n). Find n.

vladimir2022 [97]

Answer: n=4

Step-by-step explanation: 4/4=1 and 16/4=4 (1,4) n=4

7 0

2 years ago

Anybody know the answer?

german

The answer 1 because because 1-cosx^2 =sinx^2 and cotx^2+1=cscx^2 =1/sinx^2 and sinx^2/sinx^2=1
Hope, help and Heal.

5 0

3 years ago

Company A charges $35 to rent a car, plus an additional $12.50 per day. Company B charges $20 to rent a car plus $20 per day At

anyanavicka [17]

They would cost the same amount by day 2. day 1 for car a is $45.50. day 1 for car b is $40. day 2 for car a is $60. day 2 for car b is also $60.

8 0

3 years ago

Read 2 more answers

If θ is a first quadrant angle in standard position with P(u,v) = (3,4) evaluate cos 2 θ

zaharov [31]

We have to evaluate cos(2θ), knowing that θ is in the first quadrant and in standard position P(u,v) = (3,4).

We can picture this as:

We can write the relation:

$\tan \theta=\frac{4}{3}$

We now look at the identities to find cos(2θ):

$\cos (2\theta)=\frac{1-\tan^2(2\theta)}{1+\tan^2(2\theta)}$

There are many identities for cos(2θ), but this is expressed in the information we already know, so we can solve as:

$\begin{gathered} \cos (2\theta)=\frac{1-\tan^2(2\theta)}{1+\tan^2(2\theta)} \\ \cos (2\theta)=\frac{1-(\frac{4}{3})^2}{1+(\frac{4}{3})^2} \\ \cos (2\theta)=\frac{1-\frac{16}{9}}{1+\frac{16}{9}} \\ \cos (2\theta)=\frac{\frac{9-16}{9}}{\frac{9+16}{9}} \\ \cos (2\theta)=\frac{-7}{25} \end{gathered}$

Answer: cos(2θ) = -7/25

8 0

11 months ago