Answer:
7x^2 - 2x - 3.
Step-by-step explanation:
Starts with 7x^2 then a term in x then a constant.
Using it's concept, it is found that the graph has no horizontal asymptote.
<h3>What are the horizontal asymptotes of a function f(x)?</h3>
The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, we have that:
- The function is undefined for x < 0, hence
is undefined.
- For x > 0, the funciton goes to infinity, hence
.
Thus, the graph has no horizontal asymptote.
More can be learned about horizontal asymptotes at brainly.com/question/16948935
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This would be represented by the function Y = -3x + 4 C:
just remember that your slope is your X value, and on a graph it is your rise over run. since -3 is your slope, you go down -3(your rise, you go down since it is negative) and over one. its a whole number instead of a fraction because -3/1 is simplified to -3. Your Y intercept is the added number in the end of the equation. Basically they are your values in the linear equation, which is Y = mx + b
Solve the literal equation 2xy - xz = 4 for x
x = 4/(2y-z)
y =/ z/2
Triple t ⇒ 3t
add the result to u ⇒ 3t + u
multiply what you have by v ⇒ (3t + u)v
Since it is instructed not to simplify, we perform the distributive property of multiplication.
(3t + u)v = 3tv + uv
