Answer:
e. 
Step-by-step explanation:
It is given that,
The density of intergalactic space material is
kg per cubic meter.
And the volume of intergalactic space material is 
So the mass of that much intergalactic space material is,
, where 'm' is the mass, and 'v' is the volume.
Putting the values we get,


It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is 
So the volume of lead is,


So the volume of lead is
.
First the 2 bases have surface area pi*1.25^2*2
Then the side
2.5pi*4=10pi
total of 9.817+31.415
=41.232
This approximation could be further round down for this problem to 41.2
Which makes choice C the correct choice.
Answer:
b / (b/100×b)
= b / (b/50
= 50b/b
= 50
Step-by-step explanation:
brainliest plz
Answer:
I think it is C i could be wrong
Step-by-step explanation:
Answer:
x(x-4)
Step-by-step explanation: