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eduard
3 years ago
10

Polynomials are written with the exponents of the terms in _____ order.

Mathematics
2 answers:
lozanna [386]3 years ago
6 0
Answer:  "...in descending order."

There you go.
vredina [299]3 years ago
5 0

Polynomials are written with the exponents of the terms in decreasing order.

<h2>Further Explanation; </h2><h3>Polynomial </h3>
  • A polynomial is an expression that contains two or more algebraic terms. Polynomials contain exponents which are added, subtracted or multiplied.  
  • Each term of a polynomial contains a variable or variables elevated to a power and also multiplied by a coefficient.
  • The terms of a polynomial do not have square roots of variables, factional powers, nor do they have variables in the denominator of any fractions it may have.
  • Terms in a polynomial can only have variables with exponents that are whole numbers.
<h3>Order of terms in a polynomials </h3>
  • Polynomials are written with it terms being ordered in decreasing order of exponents.
  • This means that the term with the largest exponents is written first, followed by the term with the next highest exponent and so on and the constant term is written last.
<h3>Types of polynomial </h3><h3>Monomial  </h3>
  • It is a polynomial with one term.
  • For example; 3x  
<h3>Binomial  </h3>
  • It is a polynomial that consists of two unlike terms
  • For example; 3x^2 + 2x
<h3>Trinomial </h3>
  • It is a type of polynomial that consists of three unlike terms.
  • For example; 4x^3 + 2x^2 + 3x  

Keywords: Polynomial, types of polynomial, order of terms in a polynomial

<h3>Learn more about: </h3>
  • Polynomials: brainly.com/question/11333546
  • Examples of polynomials: brainly.com/question/11333546
  • Degree of polynomials: brainly.com/question/12153160

Level; High school  

Subject: Mathematics

Topic: Polynomials  

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yanalaym [24]
You know that y^2=4x so x=\dfrac{y^2}{4}.
Area of a shaded region is:

$A=\int\limits_0^k\dfrac{y^2}{4}\,dy=\frac{1}{4}\int\limits_0^ky^2\,dy=\frac{1}{4}\left[\frac{y^3}{3}\right]_0^k=\frac{1}{4}\left[\frac{k^3}{3}-\frac{0^3}{3}\right]=\frac{1}{4}\cdot\dfrac{k^3}{3}=\boxed{\frac{k^3}{12}}

so k:

\dfrac{k^3}{12}=\dfrac{9}{4}\\\\\\k^3=\dfrac{9\cdot12}{4}\\\\\\k^3=9\cdot3\\\\k^3=3^3\quad|\sqrt[3]{(\ldots)}\\\\\boxed{k=3}


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