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2 years ago

Help men on my math test :(((

Mathematics

1 answer:

Readme [11.4K]2 years ago

5 0

Answer:

Regular and hexagon

Step-by-step explanation:

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Need help now please

baherus [9]

Answer:

Step-by-step explanation:

rise over run = y/x

3/1.5= 2

8 0

2 years ago

WILL MARK BRAINLIEST NEED ANSWERS NOWW 100 POINTTTSSS.

mestny [16]

Part A:

To get the interest of 1 year

Multiply 20,000 by 5% or 0.05

You get $1,000

Thats the amount for 1 year, now to get for 4 years, multiply 1,000, by 4

She pays $4,000 in interest

Part B:

If she pays it off in 2 years, instead of 4 years, she will pay an interest of $2,000, divide 4 by 2

Part C:

This is the same as part b, she saves $2,000

Hope this helps

-GoldenWolfX

6 0

2 years ago

Evaluate f(-2) if f(x) = x + 3<br> OC<br> bh

natka813 [3]

Answer: is this 8th grade math or high school or college because i am in 8th grade

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What is -9/12 + 4/12=

Fantom [35]

Answer:

I think it would be -0.416 but I'm not real sure so make sure before using my answer! :3 Have a great day!

6 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago