Volume is a three-dimensional scalar quantity. The number of kleenex boxes that can fit in the large box is 4096.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Given the larger box have a length of the side as 4 feet. Also, the kleenex box is a cube with side lengths of 3 inches. Therefore, the number of cubes that will fit is,
Number of boxes = Volume of Larger box / Volume of kleenex box
Number of box = (4 feet)³ / (3 inches)³
Number of box = (48 inches)³ / (3 inches)³
Number of box = 4096
Hence, the number of kleenex boxes that can fit in the large box is 4096.
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Based on the given mathematical statement, it can be rewritten into a mathematical equation to simplify and to be solved easily. The statement, "When one is subtracted from three-tenths of a number" corresponds to the equation, 3x/10 - 1, that is assuming the number is represented by the variable x. This is equal to one-fifth of the number. In other words,
3x/10 - 1 = x/5
x = 10
Answer:
The answer I got was 16
16(y^2+4x^6)(y+2x^3)(y-2x^3)
Step-by-step explanation:
This is another one for my "impossible math question" file. All of the answer choices are wrong. (None applies.)
According to the problem statement, the length you have marked "x" in the diagram is 15 inches. If the side length of one of the pavers is "s", then the Pythagorean theorem tells us
s² + (2s)² = 15²
5s² = 225
s² = 225/5 = 45 . . . . . . the area of one square is 45 in² (not 225 in²)
Then
s = √45 = 3√5 . . . . . . . the length of one side is not 5√3
so the perimeter is
p = 4s = 4·3√5 in = 12√5 in ≈ 26.83 in . . . . not 75 inches.
The area of the 6-block L-shaped path is
total area = 6s² = 6·45 in² = 270 in² . . . . not 450 in²
And the total perimeter is 14 sides, so is
total perimeter = 14s = 14·3√5 in = 42√5 in . . . . not 60√3 in
_____
In cases like this where the answer key is incorrect, you might try asking your teacher show the class how to work the problem.
Answer:
12 cm ... What will be the height of the plant after 2 days? ... cm, the number of days it has been exposed to the sunlight is ______ .
