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Gala2k [10]
3 years ago
15

Lainey bought a set of 20 makers for $6 what is the cost of 1 marker? ​

Mathematics
1 answer:
loris [4]3 years ago
6 0

Answer:

0.30

Step-by-step explanation:

$6 Total

20 markers

6/20=0.30

0.3 per maker.

Cost of 1 marker is $0.30

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Please help ill give brainleist answer
wolverine [178]

Answer:

look at the picture i have sent

8 0
3 years ago
Which expression is equivalent to<br> %?
olganol [36]

Answer:

x^{\frac{2}{3} }

Step-by-step explanation:

⇒ x^({\frac{4+2}{3}) } ^{\frac{1}{3} }

⇒ (x^{\frac{6}{3} })

⇒ (x^{2} )\frac{1}{3}

⇒ x^{\frac{2}{3} }

8 0
2 years ago
Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.​
koban [17]

Answer:

x^2 + 4x + y^2 +8y  =  0

Step-by-step explanation:

Given

A = (-1,-2)

B = (2,4)

AP:BP = 1 : 2

Required

The locus of P

AP:BP = 1 : 2

Express as fraction

\frac{AP}{BP} = \frac{1}{2}

Cross multiply

2AP = BP

Calculate AP and BP using the following distance formula:

d = \sqrt{(x - x_1)^2 + (y - y_1)^2}

So, we have:

2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}

2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}

Take square of both sides

4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2

Evaluate all squares

4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16

Collect and evaluate like terms

4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20

Open brackets

4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20

Collect like terms

4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y  + 20 - 20 =  0

3x^2 + 12x + 3y^2 +24y  =  0

Divide through by 3

x^2 + 4x + y^2 +8y  =  0

3 0
3 years ago
A board is 4ft 8in long how long is the board in feet
DerKrebs [107]

the board would be 4.85 feet

5 0
3 years ago
write the restrictions that should be imposed on the variable for each of the following function. then find, explicitly, the dom
matrenka [14]

By using the rules that the value inside square root can’t be negative and the denominator value can’t be zero, the domain for the given function is a) x<-1 and x>1  b) p≤1/2  c) s>-1.

I found the complete question on Chegg, here is the full question:

Write the restrictions that should be imposed on the variable for each of the following function. Then find, explicitly, the domain for each function and write it in the interval notation a) f(x)=(x-2)/(x-1)  b) g(p)=√(1-2p)  c) m(s)= (s^2+4s+4)/√(s+1)

Ans. We know that a number is not divisible by zero and number inside a square root can not be negative. In both the cases the outcome will be imaginary.

a) For this case the denominator x-1 can not be zero. So, x ≠1 and the domain is x<-1 and x>1.

b) For this case the value inside square root can’t be negative. So, p can’t be greater than 1/2 the domain is p≤1/2.

c) For this case also the value inside square root can’t be negative and the denominator value can’t be zero. So, s can’t equal or less than -1 and domain is s>-1.

Learn more about square root here:

brainly.com/question/3120622

#SPJ4

3 0
2 years ago
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