Solve x^2+20x+100=50

Mathematics

1 answer:

uysha [10]2 years ago

6 0

1. You con solve the quadratic equation x^2+20x+100=50 by following the proccedure below:

2. Pass the number 50 from the right member to the left member. Then you obtain:

x^2+20x+100-50=0
 x^2+20x+50=0

3. Then, you must apply the quadratic equation, which is:

x=(-b±√(b^2-4ac))/2a

x^2+20x+50=0

a=1
b=20
c=50

4. Therefore, when you substitute the values into the quadratic equation and simplify ir, you obtain that the result is:

-10±5√2 (It is the last option).

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Step-by-step explanation:

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