The slope:
![m=\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
![A(2;-3)\to x_1=2;\ y_1=-3\\P(2;\ 9)\to x_2=2;\ y_2=9\\\\subtitute:\\\\m=\dfrac{9-(-3)}{2-2}=\dfrac{12}{0}!!!](https://tex.z-dn.net/?f=A%282%3B-3%29%5Cto%20x_1%3D2%3B%5C%20y_1%3D-3%5C%5CP%282%3B%5C%209%29%5Cto%20x_2%3D2%3B%5C%20y_2%3D9%5C%5C%5C%5Csubtitute%3A%5C%5C%5C%5Cm%3D%5Cdfrac%7B9-%28-3%29%7D%7B2-2%7D%3D%5Cdfrac%7B12%7D%7B0%7D%21%21%21)
<span>The denominator can not be <span>zero!
Conclusion: The slope is undenfined.
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False for every rate there is only one unit rate. there is however more than 1 rates for one unit rate. for example 4/2 would have 2/1 as a unit rate but 2/1 can have 4/2 and 8/4 as rates and so on. hope this helps good luck!
Answer:
x = 3
y = 4
hey, I am not 100% sure of the certainty of my answers, I am using what I remember about that topic but I do not know if it is right or wrong, I hope I have helped you, I did what I could.
Step-by-step explanation:
-3x + 2y = 23
5x + 2y = -17
X solution:
(you cancel the y)
-3x = 23
5x = -17
(you combine all the values above with those below)
2x = 6
(solve the ecuation normaly)
x = 6/2 = 3
Y solution:
(you replace the x)
-3(3) + 2y = 23
5(3) + 2y = -17
-9 + 2y = 23
15 + 2y = -17
(you combine all the values above with those below)
6 + 4y = 6
(solve the ecuation normaly)
4y = 0
y = 4
(I do not really know if the answer here is 0 or 4 since when passing the 4 to divide it would be 0/4 and I do not understand very well how that is solved)