Answer:
The amount after 3 years of investment is $20763 .
Step-by-step explanation:
Given as :
The principal invested = p =$15,000
The rate of interest = r = 3% compounded annually
The time period = t = 11 years
Let The Amount after 3 years = $ A
<u>From Compounded method</u>
Amount = Principal ×
Or, A = p ×
Or, A = $15,000 ×
Or, A = $15,000 ×
Or, A = $15,000 × 1.3842
Or, A = $20763
So, Amount = A = $20763
Hence The amount after 3 years of investment is $20763 . Answer
Complete the table for the function y = 0.1^x
The first step: plug values from the left column into the ‘x’ spot in the formula <u>y=0.1^x</u>.
* 0.1^-2 : We can eliminate the negative exponent value by using the rule a^-1 = 1/a. Keep this rule in mind for future problems. (0.1^-2 = 1/0.1 * 0.1 = 100).
* 0.1^-1 = 1/0.1 = 10
* 0.1^0 = 1 : (Remember this rule: a^0 = 1)
* 0.1^1 = 0.1
Our list of values: 100, 10, 1, 0.1
Now, we can plug these values into your table:
The points can now be graphed. I will paste a Desmos screenshot; try to see if you can find some of the indicated (x,y) values: [screenshot is attached]
I hope this helped!
Answer:
The maximum value of the equation is 1 less than the maximum value of the graph
Step-by-step explanation:
We have the equation .
We can know that this graph will have a maximum value as this is a negative parabola.
In order to find the maximum value, we can use the equation
In our given equation:
a=-1
b=4
c=-8
Now we can plug in these values to the equation
Now we can plug the x value where the maximum occurs to find the max value of the equation
This means that the maximum of this equation is -4.
The maximum of the graph is shown to be -3
This means that the maximum value of the equation is 1 less than the maximum value of the graph