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Paraphin [41]
2 years ago
5

Determine the amount of money you would have if you invested $15,000 dollars for 11 years at 3% annual interest compounded conti

nuously.
Please Show Your Work
Mathematics
1 answer:
tamaranim1 [39]2 years ago
8 0

Answer:

The amount after 3 years of investment is $20763  .

Step-by-step explanation:

Given as :

The principal invested = p =$15,000

The rate of interest = r = 3% compounded annually

The time period = t = 11 years

Let The Amount after 3 years = $ A

<u>From Compounded method</u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, A = $15,000 × (1+\dfrac{\textrm 3}{100})^{\textrm 11}

Or, A = $15,000 × (1.03)^{11}

Or, A = $15,000 × 1.3842

Or, A = $20763

So, Amount = A = $20763

Hence The amount after 3 years of investment is $20763  . Answer

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3 years ago
M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
Nitella [24]

Answer:

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

      =a(x+4)(x-4i)(x+4i)

      =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]

      =a(x+4)(x²-16i²)

      =a(x+4)(x²+16)      [∵i² = -1]

      =a(x³+4x²+16x+64)

Again given that M(0)= 53.12 . Putting x=0 in the polynomial

53.12 =a(0+4.0+16.0+64)

\Rightarrow a = \frac{53.12}{64}

      =0.83

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

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3 years ago
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