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Svet_ta [14]
3 years ago
6

What is the length of x? What is the length of EF? Only enter numbers in the answer boxes below:

Mathematics
1 answer:
dimaraw [331]3 years ago
7 0

Focus on triangles DFC and DFE:

  • They are both right triangles because DF is perpendicular to EC
  • DC=DE
  • DF is a common side

So, the two triangles are congruent. It follows that CF=FE, and in particular

8x=3x+15 \iff 5x=15 \iff x=3

And since x=3, the length of EF is

EF=3x+15=3\cdot 3+15=24

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Answer:

Y = X - 2 would be the answer.

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Question 5: 10 pts
victus00 [196]

Answer:

6.7i + 7.4j

Step-by-step explanation:

if the angle starts from the East (direction of positive x-axis)

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2 years ago
A<br> Write the equation for<br> line that<br> passes through (1, 1) and (-1,7)
KengaRu [80]

Answer:y=-3x+4

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(1,1) and (-1,7).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (1,1), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=1 and y1=1.

Also, let's call the second point you gave, (-1,7), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-1 and y2=7.

Now, just plug the numbers into the formula for m above, like this:

m=

7 - 1

-1 - 1

or...

m=

6

-2

or...

m=-3

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-3x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(1,1). When x of the line is 1, y of the line must be 1.

(-1,7). When x of the line is -1, y of the line must be 7.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-3x+b. b is what we want, the -3 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (1,1) and (-1,7).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(1,1). y=mx+b or 1=-3 × 1+b, or solving for b: b=1-(-3)(1). b=4.

(-1,7). y=mx+b or 7=-3 × -1+b, or solving for b: b=7-(-3)(-1). b=4.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(1,1) and (-1,7)

is

y=-3x+4

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3 years ago
If f (x) = 3x + 1 and g(x) = 2x + 1, what is the value of f (g(2))?
just olya [345]

Step-by-step explanation:

= f( g(2) )

= 3(2x + 1) + 1

= 6x + 3 + 1

= 6x + 4

= 6(2) + 4

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f(g(2)) = 16

3 0
3 years ago
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