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Harrizon [31]
3 years ago
15

Comparative financial statement data for Carmono Company follow: This Year Last Year Assets Cash $ 8.50 $ 16.00 Accounts receiva

ble 54.00 47.00 Inventory 97.50 84.40 Total current assets 160.00 147.40 Property, plant, and equipment 237.00 198.00 Less accumulated depreciation 47.20 35.40 Net property, plant, and equipment 189.80 162.60 Total assets $ 349.80 $ 310.00 Liabilities and Stockholders’ Equity Accounts payable $ 58.50 $ 48.00 Common stock 126.00 97.00 Retained earnings 165.30 165.00 Total liabilities and stockholders’ equity $ 349.80 $ 310.00 For this year, the company reported net income as follows: Sales $ 950.00 Cost of goods sold 570.00 Gross margin 380.00 Selling and administrative expenses 360.00 Net income $ 20.00 This year Carmono declared and paid a cash dividend. There were no sales of property, plant, and equipment during this year. The company did not repurchase any of its own stock this year. Required: 1. Using the indirect method, prepare a statement of cash flows for this year. 2. Compute Carmono’s free cash flow for this year.
Mathematics
1 answer:
TEA [102]3 years ago
6 0
This ain’t work 5 points ...
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The frequency distributions of two data sets are shown in the dot plots below.
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Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

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Data set 1:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:  

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}

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\text{Mean of data set 1}=2.3684\approx 2.37  

\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}

\text{Mean of data set 2}=\frac{38}{18}

\text{Mean of data set 2}=2.11

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

\text{Median of data set 2}=\frac{2+2}{2}

\text{Median of data set 2}=\frac{4}{2}=2

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.


Q_1\text{ of data set 1}=1

Q_3\text{ of data set 1}=3

\text{IQR of data set 1}=3-1=2

Q_1\text{ of data set 2}=1

Q_3\text{ of data set 2}=3

\text{IQR of data set 2}=3-1=2

Since both data set's IQR is 2, therefore, 6th statement is true.

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