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Ira Lisetskai [31]
3 years ago
5

Find the area of each figure. around to the nearest tenth if necessary.

Mathematics
1 answer:
djyliett [7]3 years ago
7 0

Answer:

68 cm²

Step-by-step explanation:

I don't see what you mean for each figure but here goes nothing!

We can split the figure in 2 rectangles

We find the first rectangle by doing 4 x 12 = 48 cm²

The second rectangle would be 5 x 4 = 20 cm²

Therfore we add them up into 20 + 48 = 68 cm²

Hope This Helps!

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The sum of the circumference of two circles is 38π cm and the sum of their areas is 193π cm². Calculate the radii of the circles
sdas [7]

Answer:

The radii of the circles are 12 cm and 7cm.

Step-by-step explanation:

Let the radii of the circles be r_{1}\ and\ r_{2}

Given:

Sum of circumference of two circles= 38π cm

Formula for circumference of a circle with radius r = 2πr

2\pi r_{1}+2\pi r_{2}=38\pi \\r_{1}+r_{2}=19------------1

Sum of areas of two circles= 193π cm²

Area of circle with radius r = πr²

\pi r_{1}^{2}+\pi r_{2}^{2}=193\pi \\r_{1}^{2}+r_{2}^{2}=193-------2

Substituting r2 = 19 - r1 in equation 2 we get:

r_{1}^{2}+(19-r_{1})^{2}=193\\2r_{1}^{2}-38r_{1}+168=0\\r_{1}^{2}-19r_{1}+84=0\\(r_{1}-12)(r_{1}-7)=0\\r_{1}=12\ or\ 7

Then r2 = 19 - r1

r_{2}=12\ or\ 7

7 0
3 years ago
The north pole is in the middle of the ocean. A person at sea level at the north pole would be 3,949 miles from the center of th
artcher [175]

Answer:

It is given that the North Pole is at a distance of 3,949 miles from the center of the earth. We also know that the sea floor is below 2.4 miles from the sea level. 3949 - 2.4 = 3946.6 miles

6 0
3 years ago
The box plot below represents some data set. What percentage of the data values are less than 61?
GenaCL600 [577]

Answer:

25%

Step-by-step explanation:

plato

6 0
3 years ago
Read 2 more answers
write an equation in point-slope form for the line that has a slope of 1/5 and contains the point (2, -9).
andriy [413]

                - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\blue\textsf{\textbf{\underline{\underline{Question:-}}}}

Write an equation in point-slope form for the line that has a slope of \bold{\dfrac{1}{5} } and contains the point (2, -9).

\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}

\sf{Formula\:for\:Point-Slope:-}

\dashrightarrow\bigstar\star\boxed{\bold{y-y_1=m(x-x_1)}}\star\bigstar\dashleftarrow

Where

y₁ = the y-coordinate of the point that the line contains

m = slope

x₁ = the x-coordinate of the point that the line contains

Provided Information:-

y₁ = -9

m = \dfrac{1}{5}

x₁ = 2

Substitute the values:-

         \sf{y-(-9)=\dfrac{1}{5} (x-2)}

    On simplification,

          \sf{y+9=\dfrac{1}{5}(x-2)}

According to the answer and explanation, we conclude that

       [<u>The correct answer is Option B]</u>

<u />

<h3><u /></h3><h3>Good luck.</h3>

   

               - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

5 0
2 years ago
In January of 2003(group 1), 1188 out of 1500 spots were bare ground (no vegetation). Find the sample proportion of bare ground
Nikitich [7]

Answer:

n= 1500 represent the random sample selected

X= 1188 represent the number of pots that were bare ground (no vegetation

\hat p=\frac{X}{n}

And replacing we got:

\hat p=\frac{1188}{1500}= 0.792

So then the sample proportion of bare ground spots is 0.792 for this sample

Step-by-step explanation:

We have the following info given from the problem:

n= 1500 represent the random sample selected

X= 1188 represent the number of pots that were bare ground (no vegetation)

And for this case if we want to find the sample proportion of bare ground spots we can use this formula:

\hat p=\frac{X}{n}

And replacing we got:

\hat p=\frac{1188}{1500}= 0.792

So then the sample proportion of bare ground spots is 0.792 for this sample

7 0
3 years ago
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