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3 years ago

NEED HELP ASAP 30 POINTS!

1 answer:

4 0

Ok, so to tackle this problem you have the speed, the time, and are looking for the distance. v=d/t, if you're familiar. Isolating d on one side, you get d=vt. Let's do just that.
d=3.6*10^-2*1.8*10^4
d=648 mm

There are 2 sig figs for both elements, so there should be 2 sig figs in the answer. (sig figs are significant figures.)
So the answer would be DG.

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What are four things a new prince should do to maintain hold of his state?

pogonyaev

Answer:

The subjects of a conquered kingdom are not used to living in freedom or standing up for themselves, and are therefore slower to take up arms than are the citizens of a republic. There are three options for the conquering prince: destroy the republic, live there, or set up a puppet government. At the end of the day, Machiavelli seems to favor the first option.

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1 year ago

1) Calcula la diagonales de un poligono n lados. Heptágono: 2 puntos

ahrayia [7]

Answer:

El número de diagonales de un polígono de n lados se calcula mediante la siguiente fórmula:

$d = \frac{n\cdot (n-3)}{2}$ (1)

Donde:

$d$ - Cantidad de diagonales del polígono.

$n$ - Cantidad de lados del polígono.

Bajo esta fórmula, tenemos los siguientes resultados:

a) El heptágono tiene 14 diagonales.

b) El octágono tiene 20 diagonales.

c) El eneágono tiene 27 diagonales.

d) El decágono tiene 35 diagonales.

e) El pentadecágono tiene 90 diagonales.

Explanation:

La cantidad de diagonales de un polígono se puede determinar mediante la siguiente ecuación:

$d = \frac{n\cdot (n-3)}{2}$ (1)

Donde:

$d$ - Cantidad de diagonales del polígono.

$n$ - Cantidad de lados del polígono.

A continuación, calculamos la cantidad de diagonales de los siguientes polígonos:

Heptágono ( $n = 7$ )

$d = \frac{7\cdot (7-3)}{2}$

$d = 14$

El heptágono tiene 14 diagonales.

Octágono ( $n = 8$ )

$d = \frac{8\cdot (8-3)}{2}$

$d = 20$

El octágono tiene 20 diagonales.

Eneágono ( $n = 9$ )

$d = \frac{9\cdot (9-3)}{2}$

$d = 27$

El eneágono tiene 27 diagonales.

Decágono ( $n = 10$ )

$d = \frac{10\cdot (10-3)}{2}$

$d = 35$

El decágono tiene 35 diagonales.

Pentadecágono ( $n = 15$ )

$d = \frac{15\cdot (15-3)}{2}$

$d = 90$

El pentadecágono tiene 90 diagonales.

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