Answer:
y = - 2(x + 4)² + 6
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k ) = (- 4, 6 ) , thus
y = a(x - (- 4) )² + 6 , that is
y = a(x + 4)² + 6
To find a substitute (- 2, - 2) into the equation
- 2 = a(- 2 + 4)² + 6 ( subtract 6 from both sides )
- 8 = a(2)² = 4a ( divide both sides by 4 )
- 2 = a , thus
y = - 2(x + 4)² + 6 ← equation in vertex form
Answer:
1) 20.9
2) 896
3) 21
Step-by-step explanation:
1) 5.6÷2^3+(12.75+7.45)
---> 12.75 + 7.45 = 20.2
÷ 
--> Simplify 2^3 to 8
÷ 8 + 20.2
--> 5.6 ÷ 8 = 0.7
--> Simplify
2) 4^3 × (0.6 +3.6) ÷ 0.3
---> 0.6 + 3.6 = 4.2
4^3 * 4.2 ÷ 0.3
---> 4^3 = 64
64 * 4.2 ÷ 0.3
--> 64 * 4.2 = 268.8
268.8 ÷ 0.3
--> 268.8 ÷ 0.3 = 896
896
3) 2^4 + (2.75 +1.75) ÷ 0.9
--> 2.75 + 1.75 = 4.5
2^4 + 4.5 ÷ 0.9
--> 2^4 = 16
16 + 4.5 ÷ 0.9
--> 4.5 ÷ 0.89 = 5
16 + 5
--> Simplify
= 21
Not sure about the question, but answer is:
3/5* 2/5 = 6/25=0.24 =24%
No.
A fifth degree polynomial, having a graph that increases and starts from below x-axis.
Therefore, no matter what equation it is. The fifth degree polynomial will intercept x-axis AT LEAST one.
The fifth degree polynomial can have only at maximum, 4 complex roots.
<em>You can try drawing or seeing the graph of fifth-degree polynomial function. No matter what equations, they still intercept at least one x-value.</em>
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Answer:
10
Step-by-step explanation:
