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Nastasia [14]
2 years ago
13

Whats the answer to this?

Mathematics
2 answers:
strojnjashka [21]2 years ago
8 0

Answer: 6

Step-by-step explanation:

Let the taco be t. Let the hat = h. Let the guitar = g.

Based on the first equation, we get 2t = 8.

Divide by 2 on both sides:

t = 4.

We can plug in the value of t into the second equation.

Then, h + 4 = 7.

So, h = 3

Plug the value of h into the third equation.

We get that 3 + g = 5.

Therefore, g = 2

We are asked to find the value of g + t:

Which is 2 + 4 = 6

jasenka [17]2 years ago
3 0
The answer I believe is 7
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Which table represents a quadratic relationship?
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In each case, the x-values are equally-spaced. Thus looking at second differences will tell you if the relation is quadratic. If the second differences are non-zero and constant, then the values have a quadratic relationship.

A. First differences are 2-4 = -2, 1-2 = -1, 0.5-1 = -0.5. Second differences are -1-(-2) = 1, -0.5-(-1) = 0.5. Since 1 ≠ 0.5, this relation is not quadratic. (It is exponential with a base of 1/2.)

B. First differences are 128-135 = -7, 105-128 = -23, 72-105 = -33. Second differences are -23-(-7) = -16, -33-(-23)=-10. Since -16 ≠ -10, this relation is not quadratic. (It is cubic, since 3rd differences are constant at +4.)

C. First differences are -23.2-(-23.4) = 0.2, -23.0-(-23.2) = 0.2, -22.8-(-23.0) = 0.2. Second differences are zero, so this is not a quadratic relation. (It is linear, with a slope of 0.2.)

D. First differences are 56-90 = -34, 26-56 = -30, 0-26 = -26. Second differences are -30-(-34) = 4, -26-(-30) = 4. These are constant (=4), so the relation is quadratic.

The appropriate choice is ...

... D. x -1 0 1 2 3 4

... f(x) 90 56 26 0 -22 -40

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4 years ago
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Convert 0.6 radians to degree measure.<br> Round your answer to the nearest hundredth.
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Helppp please ....what percent of 18 is 0.2?
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The answer is 18% of 0.2=0.036
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3 years ago
2. Create an estimated probability distribution for the time teens spend texting.
Furkat [3]

Answer:

<u><em>Hours</em></u>          0     0.5    1.0     1.5    2.0    2.5    3.0    3.5    4.0    4.5    5.0

<u><em>Frequency</em></u>* 0.2  0.09  0.25  0.18  0.11  0.07  0.05  0.02  0.01  0.02  0.01

Problem Statement:

The table shows the number of hours, to the nearest half hour per day, that teens spend texting according to a random sample of 870 teenagers aged 13–18 in a large urban city.

Hours          0     0.5    1.0   1.5  2.0   2.5  3.0  3.5  4.0  4.5  5.0

Frequency  170  82    220  153  92   58   40    15  12   18    10

Step-By-Step Explanation:

As we need the estimated probability distribution for teens spending time texting, we will be needing the total sample size.

As given in the problem statement,

<em><u>Total Sample Size = 870</u></em>

To calculate estimated probability distribution, we will convert the frequency sample into estimated probability distribution, for that:

Estimated Probability Distribution (Frequency*)=\frac{Frequency.Sample.Size.of.that.hour}{Total.Sample.Size}

<u><em>For Example:</em></u>

Estimated probability distribution that teens spend 0 hours texting=\frac{170}{870} =0.20

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Estimated probability distribution that teens spend 0.5 hours=\frac{82}{870} =0.09

Using the same formula we get:

<em><u>Hours</u></em>          0     0.5    1.0     1.5    2.0    2.5    3.0    3.5    4.0    4.5    5.0

<em><u>Frequency</u></em>* 0.2  0.09  0.25  0.18  0.11  0.07  0.05  0.02  0.01  0.02  0.01

(<em>Note: Frequency* is the estimated probability distribution)</em>

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