Answer:
Weights of at least 340.1 are in the highest 20%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

a. Highest 20 percent
At least X
100-20 = 80
So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.




Weights of at least 340.1 are in the highest 20%.
This is something to memorize
y = r*sin(theta)
so if y = 2, then
2 = r*sin(theta)
Divide both sides by sin(theta) to get
r = 2/sin(theta)
r = 2csc(theta)
6 - (-2) - 3(-5) = (6 + 2) + 15 = 8 + 15 = 23
Your answer is D. the last one :)
Answer:
The answer to your question is 1.875 gallons
Step-by-step explanation:
Data
distance = 50 mi
volume of gas = 1 gal
volume for 150 km = ?
Process
1.- Convert 50 mi into kilometers
1 mile ------------------- 1.6 km
x ------------------ 150 km
x = (150 x 1)/1.6
x = 93.75 mi
2.- Calculate the gallons wasted
1 gallon ----------------- 50 mi
x ---------------- 93.75 mi
x = (93.75 x 1)/50
x = 93.75/50
x = 1.875 gallons