Answer:
The probability of friend A winning with HH = 1/4.
Step-by-step explanation:
The probability of an event, A is P(A) given by the relationship;
P(A) = (The number of required outcome)/(The number of possible outcomes)
The parameters given are;
The condition of friend A winning = Coin toss sequence HH shows up
The condition of friend B winning = Coin toss sequence TH shows up
The number of possible outcomes = TT, TH, HH, HT = 4
(TH and HT are taken as different for the game to be fair)
The number of required outcome = HH = 1
Therefore;
The probability of friend A winning with HH = 1/4.
Add up all 3 colors first
5 + 4 + 3 = 12
5 blue balls
5 over 12
Answer:
a(6)=2430
Step-by-step explanation:
a(1)=10
a(n)=3×a(n-1)
This is a geometric sequence, with ratio=3
a(2)=3×a(1)=3×10
a(3)=3×a(2)=3²×10
a(6)=3⁵×20=(27×9)×10=243×10=2430
