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MAXImum [283]
3 years ago
6

2 divded by 18 don't tell me it's .1111111 tell me the number i sould but not .111111 plz help

Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0

Answer:

The answer is rounding you want to round to 0 or you round to 0.1 depending on how small you round

Step-by-step explanation:

Hope I helped!!!

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A number cube has sides that are labeled 1 to 6. Jamal rolls the number cube. What is the probability that he will roll a 22?
Tems11 [23]

-- The probability of rolling a 22 is zero.  That result is impossible, because the sides are labeled with single digits 1 through 6 .  Since 22 is not printed anywhere on the cube, it can never come up.

-- The probability of rolling a<em> 2</em> , however, is <em> 1/6</em> . <em>(B)</em>

<em></em>

The -probability of rolling something you want is always

<em>(the number of different possible results that you like) </em>

divided by

<em>(the total number of different possible results)</em>

4 0
3 years ago
In June Gemma paid £68 for her electricity.
Volgvan
Answer:
Total amount paid in july: $68 + $3.40 + 71.40
Step-by-step explanation:
given: June= $68 for electricty
5 0
3 years ago
Find the minimum and maximum value of the function on the given interval by comparing values at the critical points and endpoint
Kitty [74]

Answer:

maximum: y = 1

minimum: y = 0.

Step-by-step explanation:

Here we have the function:

y = f(x) =  √(1 + x^2 - 2x)

we want to find the minimum and maximum in the segment [0, 1]

First, we evaluate in the endpoints, which are 0 and 1.

f(0)  =√(1 + 0^2 - 2*0) = 1

f(1) = √(1 + 1^2 - 2*1) = 0

Now let's look at the critical points (the zeros of the first derivate)

To derivate our function, we can use the chain rule:

f(x) = h(g(x))

then

f'(x) = h'(g(x))*g(x)

Here we can define:

h(x) = √x

g(x) = 1 + x^2 - 2x

Then:

f(x) = h(g(x))

f'(x)  =  1/2*( 1 + x^2 - 2x)*(2x - 2)

f'(x) = (1 + x^2 - 2x)*(x - 1)

f'(x) = x^3 - 3x^2 + x - 1

this function does not have any zero in the segment [0, 1] (you can look it in the image below)

Thus, the function does not have critical points in the segment.

Then the maximum and minimum are given by the endpoints.

The maximum is 1 (when x = 0)

the minimum is 0 (when x = 1)

7 0
3 years ago
How u do this question
creativ13 [48]
It wont let me see the pic sorry
try again
7 0
3 years ago
Please help ASAP please do these questions
Sedbober [7]

Answer:

a- 32

b-66

c-4

d-57

I tried.

Step-by-step explanation:

4 0
3 years ago
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