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3 years ago

Help me pleaseee!!!!

Mathematics

1 answer:

Minchanka [31]3 years ago

8 0

Answer:

y = (10 + 7)/x or y = x/10 + 7/10

Step-by-step explanation:

y = 10x - 7

switch x and y

x = 10y - 7

add 7 to both sides

x + 7 = 10y

Divide both sides by 10

(x + 7)/10 = y

Flip

y = (10 + 7)/x or y = x/10 + 7/10

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You pick a card at random, put it back, and then pick another card at random.

Shtirlitz [24]

Answer:

Step-by-step explanation:

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4 0

3 years ago

37040 divided by 3600

Alex

10.3(rounded to the nearest hundredth)
10.29(Rounded to the nearest tenth)
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3 years ago

Let the function f be defined by f(x)=12-5x b)evaluate f(-1)

Alexxx [7]

F(-1) = 12 - 5(-1)
f(-1) = 12 + 5
Solution: f(-1) = 17

6 0

3 years ago

Read 2 more answers

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

4 years ago

Solve by factoring c^2=5c

muminat

Hey there!

c² = 5c

Subtract 5c from both sides:

c² - 5c = 5c - 5c

Simplify :

c² - 5c = 0

c = 5 , c = 0

6 0

3 years ago