100 POINTS AND BRAINLIEST TO WHOEVER SOLVES IT

Mathematics

2 answers:

Sergeeva-Olga [200]2 years ago

8 0

Answer:

See below ~

Step-by-step explanation:

Volume of a tetrahedon

V = s³ / 6√2

s = edge length

Solving for V

V = (4)³ / 6√2
V = 64 / 6√2
V = 32 / 3√2
V = 32√2 / 6
V = 16√2 / 3
V = 7.54 cubic inches

Graph

Butoxors [25]2 years ago

6 0

Volume of a tetrahedron with edge s

$\\ \rm\Rrightarrow V=\dfrac{s^3}{6\sqrt{2}}$

According to question

s=4in

$\\ \rm\Rrightarrow V=\dfrac{4^3}{6\sqrt{2}}$

$\\ \rm\Rrightarrow V=\dfrac{64}{6\sqrt{2}}$

$\\ \rm\Rrightarrow V=\dfrac{32}{3\sqrt{2}}$

$\\ \rm\Rrightarrow V=\dfrac{32}{4.2426406871192}$

$\\ \rm\Rrightarrow V\approx 7.5425in^3$

You might be interested in

Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the

Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

$\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3$

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}$

Now, we calculate the sum

$\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\$