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vesna_86 [32]
3 years ago
14

What is the probability that a value picked at random from the standard normal distribution will be between -1.96 and 1.96?

Mathematics
1 answer:
iren [92.7K]3 years ago
4 0

Answer:

P( -1.96 ≤ Z≤ 1.96) = 0.95

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the z -scores -1.96 and 1.96

we have to find   P( -1.96 ≤ Z≤ 1.96)

P( -1.96 ≤ Z≤ 1.96) = |A(1.96)+A(-1.96)|

                              = |A(1.96)+A(-1.96|   (∵A(-Z) = A(Z))

                            =  0.4750+0.4750

                            = 2×0.4750

                           = 0.95

The probability lies between  -1.96 to 1.96

P( -1.96 ≤ Z≤ 1.96) = 0.95

             

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