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vesna_86 [32]
3 years ago
14

What is the probability that a value picked at random from the standard normal distribution will be between -1.96 and 1.96?

Mathematics
1 answer:
iren [92.7K]3 years ago
4 0

Answer:

P( -1.96 ≤ Z≤ 1.96) = 0.95

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the z -scores -1.96 and 1.96

we have to find   P( -1.96 ≤ Z≤ 1.96)

P( -1.96 ≤ Z≤ 1.96) = |A(1.96)+A(-1.96)|

                              = |A(1.96)+A(-1.96|   (∵A(-Z) = A(Z))

                            =  0.4750+0.4750

                            = 2×0.4750

                           = 0.95

The probability lies between  -1.96 to 1.96

P( -1.96 ≤ Z≤ 1.96) = 0.95

             

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Answer:

y=cosx

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Step-by-step explanation:

The trigonometric function;

y=\cos(x) has zeroes at \frac{n\pi}{2} where n is an odd integer.

The trigonometric function; y=cot x=\frac{cosx}{sinx}. This also has zeroes at \frac{n\pi}{2} where n is an odd integer.

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3 years ago
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Phantasy [73]

Answer:

<h2>-1</h2>

Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

I don't know if this is the right way to so it, but I would do it like this

since a triangle has 180 degrees, the angles all have to add up to 180

So 180 = a + b + c

we already know a, its 95

So 180 = 95 + b + c

now we know the equation for b, so we'll just put it there instead of the b, and since the angles are the same, we should put it instead of c too

180 = 95 + (4x-15) + (4x-15)

now subtract 95 from both sides

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85 = 8x - 30

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divide by 8

your x is 14 3/8 or 14.375 or 115/8

that's not your angle, that's your x

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Step-by-step explanation:

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3 years ago
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