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3 years ago

Which function has zeroes at npi/2, where n is an odd integer. Select two of the following that apply.

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

6 0

Answer:

A, B

Step-by-step explanation:

Andrews [41]3 years ago

4 0

Answer:

$y=cosx$

$y=cotx$

Step-by-step explanation:

The trigonometric function;

$y=\cos(x)$ has zeroes at $\frac{n\pi}{2}$ where $n$ is an odd integer.

The trigonometric function; $y=cot x=\frac{cosx}{sinx}$ . This also has zeroes at $\frac{n\pi}{2}$ where $n$ is an odd integer.

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Use the quadratic formula to solve the<br> quadratic equation. SHOW ALL WORK.<br> 2 −8+41 = 0

horsena [70]

Answer:

Solving the equation $x^2-8x+41=0$ using quadratic formula we get $x=4+5i \ or \ x=4-5i$

Step-by-step explanation:

We need to solve the equation $x^2-8x+41=0$ using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i$

So, Solving the equation $x^2-8x+41=0$ using quadratic formula we get $x=4+5i \ or \ x=4-5i$

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2 years ago

Does the graph represent function?

Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

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3 years ago

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mash [69]

Answer:

20.

Step-by-step explanation:

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f(x= 3(2)^3 + 2^2 - 8

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KIM [24]

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puteri [66]

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