WORTH 10 points.

The equation 9y-6x=36 is written in standard form. What is the first step when writing an equivalent equation which solves for x

defon

The answer is D. Subtract 9y from both sides of the equation.

7 0

3 years ago

Read 2 more answers

Use the formula you learned to answer the question. If a dogsled team travels 4 kilometers in 8 minutes, what is the speed of th

bonufazy [111]

Answer

C-0.5km

Step-by-step explanation:

you can simplify both the kilometers and minutes to 1 kilometer in 2 minutes or 0.5 kilometer in 1 minute. Hope this helps!

6 0

3 years ago

Write the mixed number as a percent 2 41/50

ehidna [41]

Answer:

∴ 2 $\frac{41}{50}$ = 282 %

Step-by-step explanation:

2 $\frac{41}{50}$

= [( 2 × 50) + 41] ÷ 50

= ( 100 + 41) ÷ 50

= $\frac{141}{50}$

=( $\frac{141 }{50}$ ) × $\frac{2}{2}$

= $\frac{282}{100}$

= 282 %

∴ 2 $\frac{41}{50}$ = 282 %

7 0

3 years ago

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Myra likes blueberry yogurt, but cherry yogurt is her favorite. Yesterday, she bought 3 cartons of cherry yogurt for every 2 car

cupoosta [38]

Answer:

9 cherry, 6 blueberry

Step-by-step explanation:

lets do a table!

cherry | blueberry

----------------------------

3 2

6 4

9 6

When there are 2 blueberry, there are 3 cherry. 3 is 1 more than 2. When there are 4 blueberry, there are 6 cherry. 6 is 2 more than 4. When there are 6 blueberry, there aare 9 cherry. 9 is 3 more than 6.

7 0

2 years ago

Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere

Ket [755]

Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

Taylor series expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$