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Oxana [17]
2 years ago
5

Yoo how yall doinnnnn

Mathematics
2 answers:
ICE Princess25 [194]2 years ago
5 0

Answer:

pretty good tired of the virus stuff but good

Step-by-step explanation:

astra-53 [7]2 years ago
4 0

Answer:

Im great... how bout you?

Step-by-step explanation:

You might be interested in
Imagina que vas a un partido de béisbol con tus amigos, y tienen hambre. El costo de dos botellas de agua y 3 bolsas de palomita
Rudik [331]

Answer:

El costo de una botella de agua es de $10

El costo de una bolsa de palomitas de maíz es de $15.

Step-by-step explanation:

Los parámetros dados son;

El costo de dos botellas de agua y 3 bolsas de palomitas de maíz = $65

El costo de 4 botellas de agua y 1 bolsa de palomitas de maíz = $55

Donde x = El costo de una botella de agua ey = El costo de una bolsa de palomitas de maíz, tenemos;

2 × x + 3 × y = 65 ... (1)

4 × x + y = 55 ... (2)

Haciendo y el tema de ambas ecuaciones, tenemos;

Para la ecuación (1), tenemos;

2 · x + 3 · y = 65

3 · y = 65 - 2 · x

y = 65/3 - 2/3 · x

Para la ecuación (2), tenemos;

4 · x + y = 55

y = 55 - 4 · x

Igualando ambos valores de y para encontrar la solución común, tenemos;

65/3 - 2/3 · x = 55 - 4 · x

4 · x - 2/3 · x = 55 - 65/3

10 · x / 3 = 100/3

∴ 10 · x = 100

x = 100/10 = 10

x = 10

El costo de una botella de agua = x = $10

y = 55 - 4 · x = 55 - 4 × 10 = 55 - 40 = 15

y = 15

El costo de una bolsa de palomitas de maíz = y = $15

4 0
3 years ago
2) Subtract and simplify. 11 7\10 − 7 3\10 =
Free_Kalibri [48]

Answer:

4 2/5

Step-by-step explanation:

     11 7/10

-      7 3/10

----------------

      4 4/10

4 4/10 = 4 2/5

4 0
2 years ago
our buses carrying 140 high school students arrive to Montreal. The buses carry, respectively, 31, 43, 27, and 39 students. One
Vinvika [58]

Answer:

V(X)= 39.10

V(Y)= 40

Step-by-step explanation:

Given that

Total number of student = 140

Bus A - 31

Bus B- 43

Bus C- 27

Bus D- 39

The probability that a student was on the bus is proportional to the number of student. Eg 31/140 in bus A, 43/140 on bus B, ...

E(X) = (31*31/140) + (43*43/140)  + (27*27/140) + (39*39/140)

=  35.5

Var(X) =(31-35.5)^2 \times \dfrac{31}{140}+(43-35.5)^2 \times \dfrac{43}{140}+(39-35.5)^2 \times \dfrac{39}{140}+(27-35.5)^2 \times \dfrac{27}{140}

V(X)= 39.10

The bus driver have  1/4 probability on being on any of the buses.

E(Y) = 140/4 = 35

Var(Y)=\dfrac{(35-31)^2+(35-43)^2+(35-27)^2+(35-39)^2}{4}

V(Y)= 40

7 0
3 years ago
What is 5(a-5b)(a+b)​
Vaselesa [24]

Answer:

10a-20b

Step-by-step explanation:

5a-25b+5a+5b

10a-20b

5 0
3 years ago
I need help with number 16 please.
Ugo [173]
Do it ur self etc so don't ask me
8 0
2 years ago
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