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2 years ago

If f (x) = mx+c, f(4) = 11 and f (5)=13 find value of m and c

Mathematics

1 answer:

inysia [295]2 years ago

8 0

m=2 and c=3

see the attachment for the detailed solution

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Mark ran 875 miles in the track club this year . Mark ran in 52 track meets and ran the same number of miles in each . how many

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16 $\frac{43}{52}$

Step-by-step explanation:

875/52 = 16 $\frac{43}{52}$

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2 years ago

Please help me i dont understand

irina [24]

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Step-by-step explanation:

We have a product of 3 and x. That's rewritten as 3x. We then have 4 more, so we add 4. That gives us the final answer of: 3x+4. (It is 1-4x for the third one). ( The fourth one) The sum of seven and the quotient of a number x and eight

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3 years ago

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3 years ago

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Circles c and c are similar state the translation rule and the scale factor of dilation

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Step-by-step explanation:

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3 years ago

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

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3 years ago

If f (x) = mx+c, f(4) = 11 and f (5)=13 find value of m and c​

If f (x) = mx+c, f(4) = 11 and f (5)=13 find value of m and c