Answer:
its answer is option b 15.625
The nature of a graph, which has an even degree and a positive leading coefficient will be<u> up left, up right</u> position
<h3 /><h3>What is the nature of the graph of a quadratic equation?</h3>
The nature of the graphical representation of a quadratic equation with an even degree and a positive leading coefficient will give a parabola curve.
Given that we have a function f(x) = an even degree and a positive leading coefficient. i.e.
The domain of this function varies from -∞ < x < ∞ and the parabolic curve will be positioned on the upward left and upward right x-axis.
Learn more about the graph of a quadratic equation here:
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It’s none because 8 doesn’t have a symmetry point
Hello from MrBillDoesMath!
Answer:
Choice E and F
Discussion:
From the quadratic formula with a = 3, b = -1, and c = 6
x = ( -b +\- sqrt(b^2 - 4ac) ) / (2a) => substitute in a,b,c from above
x = ( -(-1) +\- sqrt((-1)^2 - 4(3)(6)) / (2*3) => discriminant = 1 - 72 = -71)
x = ( 1 +\- sqrt(-71))/ 6
which are choices E and F
Thank you,
MrB