Answer:
Distance of JK = 15 unit
Step-by-step explanation:
Given:
J(4,8)
K(-1,-2)
Find:
Distance of JK
Computation:
Distance = √(x₂-x₁)² + (y₂-y₁)²
Distance of JK = √(-1-4)² + (-2-8)²
Distance of JK = √25 + 100
Distance of JK = √125
Distance of JK = 15 unit
Answer:
20:5 - If you're going to simplify it, do 20/5 which is 4/1.
Step-by-step explanation:
3 - (7a + 1) =
3 - 7a - 1 =
-7a + 2 <===
Answer:
a line segment in the correct answer
