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Vadim26 [7]
3 years ago
9

Jay on started off his penny collection with 1 penny. He then adds 5 pennies to his collection each day. How could you change th

e above scenario to make it a geometric series rather than an arithmetic series?
Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

By doubling each day

Step-by-step explanation:

Jay is increasing  daily a fixed amount of pennies to his collection.  That's an arithmetic series, because to obtain the next term you have to do an addition.

To get a geometric series or progression you have to find the next term through multiplication.

So, if he wants to convert his series into a geometric series, he'd have to double his contribution to his collection each day (as an example).

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4(10x+6)--10(9x+9)<br>please show your work​
Lynna [10]

Answer:

x = -1.32

Step-by-step explanation:

I expect '--' means equals to '=' in your question

4(10x+6)--10(9x+9)

4(10x+6)=10(9x+9)

40x +24 = 90x +90

40x - 90x = 90 - 24

-50x = 66

x = -66/50

x = -1.32

3 0
3 years ago
Attachment Below: For anyone who likes Brain Puzzles: Help PLS! Lol I suck at math
amm1812
The correct code is CAHF.
8 0
3 years ago
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Penelope determined the solutions of the quadratic function by completing the square. F(x) = 4x2 8x 1 –1 = 4x2 8x –1 = 4(x2 2x)
Ymorist [56]

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

<h3>What is quadratic equation ?</h3>

Any equation of the form ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called quadratic equation .

Given work of Penelope is

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+1=4\left(x^{2}+2 x+1\right) \\&0=4(x+2)^{2} \\&0=(x+2)^{2} \\&0=x+2 \\&-2=x\end{aligned}$$

Now we can see that Penelope determined the solutions of the quadratic function by completing the square. so he must have been done as following

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+4=4\left(x^{2}+2 x+1\right) \\&3=4(x+2)^{2} \\&\frac{3}{4} =x+2)^{2} \\&\frac{\pm\sqrt3}{2} =x+2 \\&\frac{-2\pm\sqrt3}{2} =x\end{aligned}$$

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

To learn more about quadratic equations visit : brainly.com/question/1214333

8 0
2 years ago
PLEASE HELP WITH ALGEBRA QUESTION NEED ASAP!!
Delvig [45]

Answer:

The function f(x) = ln(x - 4) is graphed the question options

Step-by-step explanation:

* Lets study the the information of the problem

- The graph of a logarithmic has a vertical asymptote at x=4

* That means the curve gets closer and closer to the vertical line x = 4

  but does not cross it

- It contains the point (e+4, 1)

* That means if we substitute x = e + 4 in the equation the value

 of y will be equal to 1

- It has an x-intercept of 5

* That means if we substitute y = 0 in the equation the value of x

  will be equal to 5

* Lets find the right answer

∵ f(x) = ln(x - 4)

* To find the equation of the asymptote let x - 4 = 0

∵ x - 4 = 0

∴ x = 4

∴ f(x) has a vertical asymptote at x = 4

* Lets check the point (e + 4 , 1) lies on the graph of the f(x)

∵ x = e + 4

∴ f(e+4) = ln(e + 4 - 4) = ln(e)

∵ ln(e) = 1

∴ The point (e+4 , 1) lies on the graph of the function f(x)

* To find the x-intercept put y = 0

∵ f(x) = 0

∴ ln(x - 4) = 0

* Change the logarithmic function to the exponential function

- The base of the ln is e

∴ e^0 = x - 4

∵ e^0 = 1

∴ x - 4 = 1 ⇒ add 4 to the both sides

∴ x = 5

* The function f(x) = ln(x - 4) is graphed the question options

3 0
3 years ago
What is 8690 rounded off to the neareset hundred?<br>am just asking​
Lelu [443]

Answer:

8700

Step-by-step explanation:

If it is 8,690 and you round to the nearest hundred it would add one to 90 making it 8,700

3 0
3 years ago
Read 2 more answers
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