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<h3>Answer : y = ⅚x - 3</h3>
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<h3>Known</h3>
x1 = 6
y1 = 2
x2 = (-6)
y2 = (-8)
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<h3>Question</h3>
Equation of the line (y = mx + c)
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<h3>Way to do</h3>
#First, you find the gradient (m)
#Now use the formula of equation of the line
y - y1 = m(x - x1)
y - 2 = ⅚(x - 6)
y - 2 = ⅚x - 5
y = ⅚x - 5+2
y = ⅚x - 3
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Answer:
I think the answer is A but I am not for sure
Step-by-step explanation:
hello :<span>
<span>an equation of the circle Center at the
O(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = AO
r² = (AO)²
r² = (4-0)² +(5-0)² = 16+25=41
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through B(4, 5) is : x² +y² = 41</span></span>
x² +y² - 41=0
