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lapo4ka [179]
3 years ago
9

(w^2/3v^3)^4 write answer without parentheses

Mathematics
1 answer:
ikadub [295]3 years ago
8 0

Answer:

(w^8)/81v^12

Step-by-step explanation:

First we apply exponent rule:

\frac{(w^{2})^{4}  }{(3v^{3})^{4} }

Then we simplify

\frac{w^{8} }{81v^{12} }

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Which of the follwing is not a pythagorean triple 10,16 19<br>8,15,17<br>16,63,65<br>11,60,61​
zaharov [31]

Answer:

Step-by-step explanation:

4 0
3 years ago
Laura rented a movie. She started the movie at 11:32 am and it ended at 2:19pm. How long was the movie?
Kay [80]

Answer:

2 hours and 32 minutes

Step-by-step explanation:

John Read a book at 11:32 and stopped at 2:14

What you have to do is add minutes up and hours up until you get to 2:14pm and all the hours and minutes it took to get there you add up and thats ur answer :)

7 0
3 years ago
Name the intersection of plane ABC and plane LOD
Alchen [17]

Answer:

segment AD

Step-by-step explanation:

LOD is the far side of the cube.

ABC is the left side.

So the intersection is the vertical EDGE AD, on the far-left.

4 0
4 years ago
Simplify the expression.
musickatia [10]

4(10n² - 2) - 5(8n² + 7) =

= 40n² - 8 - 40n² - 35 =

= 40n² - 40n² - 8 - 35 = -43 ← the end

6 0
3 years ago
(TIMED HELP) The population model describing the population of antelope in an area is:
Elena L [17]

Answer:

Step-by-step explanation:

The population model describing the population of antelopes in the area is

Pn+1 = [1.75(Pn)^2/(Pn-1)] + 32 - Pn

where n represents the number of years.

In the first year, the number of antelopes is given as 89, to find the number of antelopes for the second year, it means we are looking for P(1+1) = P2. We will substitute 1 for n and 89 for Pn+1

It becomes

Pn+1 = [1.75(Pn)^2/(Pn-1)] + 32 - Pn

P2 = [1.75×89^2 / (89 - 1)] + (32 -89)

P2 = [13861.75 / 88] - 57

P2 = 101

To find P3, we will substitute 101 for Pn+1 and 2 for n. It becomes

P3 = [1.75×101^2 / (101 - 1)] + (32 -101)

P3 = [17851.75 / 100] - 69

P3 = 110

To find P4, we will substitute 110 for Pn+1 and 3 for n. It becomes

P4 = [1.75×110^2 / (110 - 1)] + (32 -110)

P4 = [21175 / 109] - 78

P4 = 116

To find P5, we will substitute 116 for Pn+1 and 4 for n. It becomes

P5 = [1.75×116^2 / (116 - 1)] + (32 -116)

P5 = [23548 / 115] - 84

P5 = 121

To find P6, we will substitute 121 for Pn+1 and 5 for n. It becomes

P6 = [1.75×121^2 / (121 - 1)] + (32 -121)

P6 = [25621.75 / 120] - 89

P6 = 125

To find P7, we will substitute 125 for Pn+1 and 6 for n. It becomes

P7 = [1.75×125^2 / (125 - 1)] + (32 -125)

P7 = [27343.75 / 124] - 93

P7 = 128

To find P8, we will substitute 128 for Pn+1 and 7 for n. It becomes

P8 = [1.75×128^2 / (128 - 1)] + (32 -128)

P8 = [28672 / 127] - 96

P8 = 130

To find P9, we will substitute 130 for Pn+1 and 7 for n. It becomes

P9 = [1.75×130^2 / (130 - 1)] + (32 -130)

P9 = [29575 / 129] - 98

P9 = 131

To find P10, we will substitute 131 for Pn+1 and 7 for n. It becomes

P10= [1.75×131^2 / (131 - 1)] + (32 -131)

P10= [30031.75 / 130] - 99

P10 = 132

The correct option is C

6 0
4 years ago
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