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cricket20 [7]
3 years ago
15

The revenue from selling x tickets is r(x) = 10x. The cost for buying x tickets is c(x) = 8x + 40. The profit from selling x tic

kets is p(x) = r(x) – c(x).9. What is p(x)? *
Mathematics
2 answers:
Andrei [34K]3 years ago
6 0

Answer:

p(x)=2x-40

Step-by-step explanation:

Substitute the variables

p(x)=10x-(8x+40)

p(x)= 10x-8x-40

p(x)=2x-40

blagie [28]3 years ago
4 0

Answer:

p(X) = r(X) - c(X).9

⇔ p(X) = 10x - (8x+ 40).9

⇔ p(X) = 10x - 72x - 360

⇔ p(X) = -62x - 360

Step-by-step explanation:

You might be interested in
What is the measurement of the longest line segment in a right rectangular prism that is 26 inches long, 2 inches wide, and 2 in
EastWind [94]

Answer:

6\sqrt{19} \approx 26.153 inches.

Step-by-step explanation:

The longest line segment in a right rectangular prism is the diagonal that connects two opposite vertices. On the first diagram attached, the green line segment connecting A and G is one such diagonals. The goal is to find the length of segment \mathsf{AG}.

In this diagram (not to scale,) \mathsf{AB} = 26 (length of prism,) \mathsf{AC} = 2 (width of prism,) \mathsf{AE} = 2 (height of prism.)

Pythagorean Theorem can help find the length of \mathsf{AG}, one of the longest line segments in this prism. However, note that this theorem is intended for right triangles in 2D, not the diagonal in a 3D prism. The workaround is to simply apply this theorem on two different right triangles.

Start by finding the length of line segment \mathsf{AD}. That's the black dotted line in the diagram. In right triangle \triangle\mathsf{ABD} (second diagram,)

  • Segment \mathsf{AD} is the hypotenuse.
  • One of the legs of \triangle\mathsf{ABD} is \mathsf{AB}. The length of \mathsf{AB} is 26, same as the length of this prism.
  • Segment \mathsf{BD} is the other leg of this triangle. The length of \mathsf{BD} is 2, same as the width of this prism.

Apply the Pythagorean Theorem to right triangle \triangle\mathsf{ABD} to find the length of \mathsf{AB}, the hypotenuse of this triangle:

\mathsf{AD} = \sqrt{\mathsf{AB}^2 + \mathsf{BD}^2} = \sqrt{26^2 + 2^2}.

Consider right triangle \triangle \mathsf{ADG} (third diagram.) In this triangle,

  • Segment \mathsf{AG} is the hypotenuse, while
  • \mathsf{AD} and \mathsf{DG} are the two legs.

\mathsf{AD} = \sqrt{26^2 + 2^2}. The length of segment \mathsf{DG} is the same as the height of the rectangular prism, 2 (inches.) Apply the Pythagorean Theorem to right triangle \triangle \mathsf{ADG} to find the length of the hypotenuse \mathsf{AG}:

\begin{aligned}\mathsf{AG} &= \sqrt{\mathsf{AD}^2 + \mathsf{GD}^2} \\ &= \sqrt{\left(\sqrt{26^2 + 2^2}\right)^2 + 2^2}\\ &= \sqrt{\left(26^2 + 2^2\right) + 2^2} \\&= 6\sqrt{19} \\&\approx 26.153\end{aligned}.

Hence, the length of the longest line segment in this prism is 6\sqrt{19} \approx 26.153 inches.

5 0
3 years ago
Find the common ratio of the following geometric sequence 5/12, 1/4 , 3/20,9/100,27/500
mixas84 [53]
All you have to is divide two consecutive terms to calculate the common ratio

1/4 divided by 5/12 = 1/4 * 12/5 = 12/20 = 3/5
7 0
3 years ago
(2<br> 2X 2<br> −3 ÷ 2<br> 5<br> )<br> 2 =
Pavlova-9 [17]

Answer

Extract form = 2194 /25

Decimal form =87.76

4 0
3 years ago
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
HELP QUESTION NUMBER FOUR
enyata [817]

Answer:

x = -1 and y = -1.

Step-by-step explanation:

The given system of equations are :

y = 4x + 3 ....(1)

y = -x - 2 ....(2)

From equation (1) and (2) :

4x + 3 = -x - 2

Taking like terms together,

4x + x = -3 -2

5x = -5

x = -1

Put the value of x in equation (1)

y = 4(-1) + 3

= -1

The solution is also shown in the attached figure. Hence, the solution is x = -1 and y = -1.

5 0
3 years ago
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