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lord [1]
3 years ago
8

Franklin deposited $75 in a no-interest bank account when he opened it. After that, he deposits $50 per month in the account. As

sume he makes no other withdrawals or deposits. The equation below can be used to find m , the number of months it will take him to save a total of $175.
75 + ?m = 175
What number should he use as the coefficient of m?
50
75
125
175
Mathematics
1 answer:
luda_lava [24]3 years ago
8 0

Answer:

50

Step-by-step explanation:

The coefficient is amount of money in m (months)

The 50 is the amount of money

They are depositing $50 per month, 50m

Therefore, the coefficient is 50.

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Classify a triangle with vertices A(1, 1), B(4, 7), and C(7, 1) as one of the following.
mash [69]
B. Isosceles.  that is the correct answer
3 0
3 years ago
The volume of a cylinder of radius 3r and height 6r is given by TT(3r)2(6r). Simplify the expression.
OLga [1]

Answer: \pi 36r^{2}

Step-by-step explanation:

ALRIGHT ARE YOU READY FOR EPIC MATH TIME?

because i know i am. so lets get this bread.

WATCH: we have \pi (3r)2(6r)

interesting... that first character is called pi. maybe i should have said, "lets get this pi".

so now lets do some algebra. i am going to work from right to left. lets multiply 6r by 2. that gives us 12r. now we have... \pi (3r)(12r)

WE ARE MAKING EPIC PROGRESS, AREN'T WE?

lets multiply 12r by 3r. then we have....

\pi 36r^{2}

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so your simplified expression is: \pi 36r^{2}

6 0
3 years ago
Solve for x in the equation 2x^2+14x+17=-96
goblinko [34]
2x^{2}+14x+17=-96 \newline
2x^{2}+14x+113=0 \newline
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5 0
3 years ago
There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
3 years ago
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