Find the smallest natural number that is a multiple of 45 and where all of its digits are zeros and ones.
1 answer:
Answer:
1111111110
Step-by-step explanation:
45 is 9, and 5.
9 divisibility rule: Digits have to add up to 9.
We know this has to be 1's and 0's.
So there has to be 9 1's.
111111111.
5 divisibility rule: Last digit has to be 0 or 5.
1111111110 will be our final answer.
Wait- let's check if it's divisible. Using a calculator, this determines it does work.
Enjoy.
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Answer:
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3- 0.14 2- 841
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Answer:
6.71
You use pythagoras so you do:
6² + 3² = 45
square root 45 =6.71
