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2 years ago

Find the 13th term of the geometric sequence 3, -15, 75, ...

Mathematics

2 answers:

Maksim231197 [3]2 years ago

6 0

Step-by-step explanation:

$an = a1 + (n - 1)d \\ d = a2 - a1 \\ a1 = 3 \\ a2 = - 15 \\ d = - 15 - 3 = - 18$

$a13 = 3 + (12) \times ( - 18) \\ a13 = 3 - 216 \\ a13 = - 213$

likoan [24]2 years ago

3 0

the terms of geometric sequence are 3, -15, 75

given,

1st term (a) = 3

second term (t2)=-15

common ratio (r) = t2/t1

=-15/3

=-5

then

t13= ar^n-1

=3×(-5)^13-1

=3×244140625

=732421875.

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3 years ago

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3 years ago

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Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

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Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

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$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

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3 years ago

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How do I solve for X if I have something like this? (x+2)(1-x)= -4

lakkis [162]

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3 0

3 years ago

Find the 13th term of the geometric sequence 3, -15, 75, ...​

Find the 13th term of the geometric sequence 3, -15, 75, ...