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2 years ago

Find the 13th term of the geometric sequence 3, -15, 75, ...

Mathematics

2 answers:

Maksim231197 [3]2 years ago

6 0

Step-by-step explanation:

$an = a1 + (n - 1)d \\ d = a2 - a1 \\ a1 = 3 \\ a2 = - 15 \\ d = - 15 - 3 = - 18$

$a13 = 3 + (12) \times ( - 18) \\ a13 = 3 - 216 \\ a13 = - 213$

likoan [24]2 years ago

3 0

the terms of geometric sequence are 3, -15, 75

given,

1st term (a) = 3

second term (t2)=-15

common ratio (r) = t2/t1

=-15/3

=-5

then

t13= ar^n-1

=3×(-5)^13-1

=3×244140625

=732421875.

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Nostrana [21]

Multiply 2,500 by 1.50 which is B.

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2 years ago

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According to the US Census, Virginia had about 7.1 million residents in 2000. Of those, 24.6% were under age 18. To the nearest

Mazyrski [523]

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2 years ago

6. Santiago Diaz Granados played an arcade game that cost 25 tokens per game. In six games, Santiago won 0 tokens, 10 tokens, 50

Pavel [41]

-- To play the six games, Santiago Diaz Granados spent

(6 x 25) = 150 tokens.

-- As a result of his skill, experience, talent, steady hand, nerves
of steel, superior hand-eye coordination, and superb reflexes, 
Santiago Diaz Granados won

(0 + 10 + 50 + 0 + 5 + 10) = 75 tokens.

-- At the end of the 6th game, Santiago Diaz Granados was behind
the curve.
After spending 150 tokens and winning 75 tokens, Santiago Diaz Granados
was down by (150 - 75) = 75 tokens since he arrived at the arcade.
Any true friend could look at the choices, could see that choice-B is
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2 years ago

Sample Size for Proportion As a manufacturer of golf equipment, the Spalding Corporation wants to estimate the proportion of gol

Dima020 [189]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume an estimated proportion of $\hat p =0.5$ since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

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2 years ago

What is the slope of the line that passes through (10,0) and is parallel to y = (1/2)x + 3?

faltersainse [42]

Y=1/2x+c
0=1/2 (10)+c
0=5+c
c=-5

the equation is y=1/2x+5
the slope is the same since these two lines are parallel

4 0

2 years ago

Find the 13th term of the geometric sequence 3, -15, 75, ...​

Find the 13th term of the geometric sequence 3, -15, 75, ...