Answer : The value of angle B and angle D is 25⁰ and 35⁰ respectively.
Step-by-step explanation :
As we know that the opposite angles are equal in parallelogram.
According to the given figure,
∠A = ∠C
and
∠B = ∠D
Given:
∠B = (3n - 5)⁰
∠D = (2n + 15)⁰
From this we conclude that:
∠B = ∠D
(3n - 5)⁰ = (2n + 15)⁰
3n - 5⁰ = 2n + 15⁰
3n - 2n = 15⁰ - 5⁰
1n = 10⁰
n = 10⁰
∠B = (3n - 5)⁰ = (3×10 - 5)⁰ = 25⁰
∠D = (2n + 15)⁰ = (2×10 + 15)⁰ = 35⁰
Therefore, the value of angle B and angle D is 25⁰ and 35⁰ respectively.
$12.75-$11.25= $1.50, $9.75-$1.50= $8.25 his little brother should get $8.25 hope it helps
This answer is Y=-1/2x+11 I believe
Answer:
B. 
Step-by-step explanation:
Since 3.74 is rounded to the hundredths place, it is not the ideal exact solution for m^2 = 14.
To solve for m you would have to square root m and 14, which gives you
. This is the best answer for the problem.
Answer:
c) Is not a property (hence (d) is not either)
Step-by-step explanation:
Remember that the chi square distribution with k degrees of freedom has this formula

Where N₁ , N₂m ....
are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.
Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true
The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.