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3 years ago

GUYS I NEED HELPPPPPP PLEASEEEEEEEEEEE IF YOU CAN THEN TYSM

Mathematics

1 answer:

love history [14]3 years ago

7 0

Answer:

198 cubic metres

Steps:

Find the area of cross section

Area if traingle + Area of square

1/2 × 3 × 4 + 4×4

6+ 16

22

Then times with the lenght (9)

22×9

I hope this helps, dont hesitate to ask for any question.

Mark me as brainliest is appreciated.Tq!!

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For which equations below is x = –3 a possible solution? Check all that apply.

Tju [1.3M]

What are the options

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3 years ago

A university with a high water bill is interested in estimating the mean amount of time that students spend in the shower each d

Bas_tet [7]

Answer: $(4.0845,\ 6.5755)$

Step-by-step explanation:

As per given , we have

n = 11

$\overline{x}=5.33\\\\ s=1.33$

Since population standard deviation is missing, so we use t-test.

Critical t-value for 99% confidence :

$t_{\alpha/2,\ n-1}=3.106$ [using two-tailed t-value table]

Confidence interval :

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}\\\\= 5.33\pm (3.1060)\dfrac{1.33}{\sqrt{11}}\\\\\approx5.33\pm1.2455\\\\=(5.33-1.2455,\ 5.33+1.2455)\\\\=(4.0845,\ 6.5755)$

Hence, 99% confidence interval for the mean amount of time that students spend in the shower each day.= $(4.0845,\ 6.5755)$

7 0

3 years ago

Graph these equations: x+2y=6, y=-1/2x+4 How many solutions does the system of equations have?

inysia [295]

Answer:

The system has no solution

Step-by-step explanation:

we have

$x+2y=6$

Isolate the variable y

$2y=-x+6$

Divide by 2 both sides

$y=-\frac{x}{2}+3$ ---> equation A

$y=-\frac{x}{2}+4$ ---> equation B

Compare the equations

Equation A and equation B have the same slope and different y-intercept

Remember that

If two lines have the same slope, then the lines are parallel

The solution of the system is the intersection point both graphs

In this problem, the lines don't intersect, therefore, the system has no solution

using a graphing tool

The graph in the attached figure

7 0

3 years ago

Part 2. State what additional information is required in order to know that the triangles are congruent by ASA.

Helga [31]

<h3>Answer: Choice D. $\angle SQR \cong \angle XQR$ </h3>

The red angle markers show those two angles are congruent. That's one "A" of "ASA". The S refers to a congruent pair of sides. We don't have any tickmarks to indicate congruent pairs; however, we do know that QR = QR is a shared side that overlaps (reflexive theorem). So this is the "S" in "ASA".

The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that $\angle SQR \cong \angle XQR$ , then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

7 0

3 years ago

creativ13 [48]

Step-by-step explanation:

since the house, the school and the grocery store all have the same x coordinate (-4), they are on the same vertical line of x = -4.

and that means their distances are simply the differences in their y coordinates.

the only one different in that regard is the community center, but it is on the same y coordinate as the school, so the distance to the school is only the difference in their x coordinates.

so, the distance from house to school is

|5 - 3| = |3 - 5| = 2

as it is the same distance in either direction.

the distance from house to school to grocery store is the distance from house to school plus the distance from school to grocery store :

2 + |3 - -9| = 2 + |-9 - 3| = 2 + 12 = 14

now we need to find the distance from home to school to community center.

that is 2 + the distance from school to community center.

as mentioned above, since the school and the community center have the same y coordinate, their distance is the difference in their x coordinates :

|-4 - 6| = |6 - -4| = 10

so, in total the way house to school to community center is 2 + 10 = 12.

and that is shorter than the way house to school to grocery store, which is 14.

so, yes, the distance house to school to grocery store (14) is greater than the distance house to school to community center (12).

8 0

2 years ago