Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
Count by 1s or 5s. Write the first five numbers you would count, starting at 15.Starting by 1s
1. 16
2. 17
3. 18
4. 19
5. 20
Next is by 5s
1. 20
2. 25
3. 30
4. 35
5. 40
We need to find the Lowest Common Denominator = LCD lowest is 100
10 x 10, 20, 30, 40, 50, 60, 70, 80, 90, 100
100 x 100, 200, 300, 400, 500, 600, 700, 800, 900, 1000. which is the lowest and common? 100
7/10 /100 how many times can 10 go into 100? 10 times. so we will multiply 10 time the numerator which is 7, and now will be 70/100
6/100 /100 how many times can 100 go into 100? 1 time. so we will multiply 1 time the numerator 6 which equals 6. 6/100
now add the new fractions. 70/100 + 6/100 = 76/100
Answer:
Is there a diagram that could help??
Step-by-step explanation:
Answer:
5?
Step-by-step explanation:
