The probability of drawing only one red card in two draws without replacement is given by:

The probability of drawing two red cards in two draws without replacement isgiven by:

The events 'draw one red card' and 'draw two red cards' are mutually exclusive. Therefore the probability of drawing at least one red card is 0.51 + 0.245 = 0.755.
X=3
LOM and KOL are equivalent, so the equation is 43=6x+25 :)
The answer is -2.21428571429