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butalik [34]
3 years ago
6

Can someone please help me factor and write the equations for these two problems ?

Mathematics
1 answer:
prisoha [69]3 years ago
5 0

Answer:

Step-by-step explanation:

Asymptotes 3

g(x) = \frac{3x}{x^2-3x-10}

Factors of denominator will be,

x² - 3x - 10 = x² - 5x + 2x - 10

                 = x(x - 5) + 2(x - 5)

                 = (x + 2)(x - 5)

Therefore, factored form of g(x) will be,

g(x) = \frac{3x}{(x + 2)(x - 5)}

Asymptotes 4

h(x) = \frac{(x-5)}{x^{2} + 14x + 40}

      = \frac{x-5}{x^{2}+10x+4x+40}

      = \frac{x-5}{x(x+10)+4(x+10)}

      = \frac{x-5}{(x+10)(x+4)}

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En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

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3 years ago
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sashaice [31]

Answer:

i'm not too good in this, but i believe the answer is -3

Step-by-step explanation:

the hcf, highest common factor, of both -3 and -15 is -3, hence making the answer -3? if this is incorrect, i apologize.

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2 years ago
HELP MEEE! I NEED IT RIGHT NOW!
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given data

Cost of bicycle= $282

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let us find the sales tax

=4/100*282

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=$11.28

Hence the sales tax is $11.28

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