PLS HELP WILL GIVE BRANLIEST PLUS 15 POINTS

What are the correct answers?

DochEvi [55]

Step-by-step Answer:

Situations with dot-products.

dot-product of vectors A<xa,ya>, B<xb,yb>

is defined as A.B=xa*xb + ya+yb

Note that the result is a scalar even though A and B are both vectors.

Q1 dot product is positive

Q2 dot product is negative

The dot product is also equal to the length of the projection of the unit vector of one onto the other, multiplied by the magnitudes. This implies that the sign will be positive if the angle between the vectors is acute, and negative if the angle between them is obtuse. That makes the first two proposed answers (A, B) correct.

Q3 dot product equals 0

Since the projection of any vector onto another perpendicular to it is zero, so the dot product of two perpendicular vectors always equal zero. That makes the third proposed answer (E) correct.

Q4 dot product equals the product of the vectors' magnitudes.

The earlier statement

"The dot product is also equal to the length of the projection of the unit vector of one onto the other, multiplied by the magnitudes."

makes the fourth statement true if the unit vector projected onto the other remains a unit vector, i.e. when the two vectors are parallel (D)

Q5 dot product equals opposite of the product of the vectors.

To have the dot product's absolute value equal the product of the magnitudes, the vectors must be parallel. If the dot product is positive, then the vectors are parallel and pointing in the same direction, as in Q4.

If the dot product is negative, meaning that is the opposite of the product of the magnitudes (themselves are always positive or zero), then the vectors are parallel, but in the opposing directions.

There is no correct answer for this case, which is definitely NOT "not possible". The closest one is (D) vectors are parallel, but answer is incomplete.

Q6 dot product is greater than the product of the vectors' magnitudes.

I do not see a possible case for this to happen.

6 0

3 years ago

A cabbage palmetto has a height of 80 feet. what is the approximate height of the tree in meters?

frutty [35]

1 foot is about 0,3 meters.
If the height of the cabbage palmetto is 80 feet, it should be about 80*0,3 = 24 meters.

So a cabbage palmetto with 80 feet of height is about 24 meters.

Hope this helps! :)

6 0

3 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

HELP PLSS I HAVE 10 minutes

omeli [17]

Answer:

h≈1.43

Step-by-step explanation:

Simply ,Square the radius, and then divide the radius squared into the tripled volume. For this example, the radius is 2. The square of 2 is 4, and 300 divided by 4 is 75. Divide the amount calculated in Step 2 by pi, which is an unending math constant that begins 3.14, to calculate the cone's height.

4 0

3 years ago

An integer from 300 through 780, inclusive is to be chosen at random, find the probability that the number is chosen will have 1

exis [7]

Answer:

93/481

Step-by-step explanation:

Total number of integers from 300 through 780, inclusive:

780 - 299 = 481

Number of integers with at least one of digit 1:

Hundreds - 0,
Tens - 5*10 = 50 (31th, 41th, 51th, 61th, 71th)
Units - 4*9 + 7 = 43 (300 till 699 and 700 till 780)
So in total 50 + 43 = 93

The probability is:

P = favorable outcomes/total outcomes = 93/481

6 0

3 years ago