1) the types of number are the negative integers (e.g √-1 √-3 <span>√-5 are not defined)
2) the answer is No, proof: 2x</span>√-1 is not defined because <span>√-1 doesn't exist
3) the answer is No, proof: </span>√-1 - 3 is not defined because √-1 doesn't exist
4) the answer is Yes, proof: (√-1 )²= -1 this is a real number
5) the answer is No, proof: (√-1 )^3= (√-1 )²(√-1 )= - 1(√-1 ), and - 1(√-1 ) is not defined because √-1 doesn't exist
6) the result would be defined with the following cases:
√-1+n, n>1
√-1xn, n<0
√-1/n, n<0
7) the result would not be defined with the following cases:
√-1+n, n<0
√-1xn, n>0
√-1/n, n>0
8) to square <span>3 + √-1, I use the method of complex number
i²= -1, it implies i= </span>√-1
so 3+√-1=3+i, and then (3+√-1)²=(3+i)²= 9 -1+6i= 8-i= 8-√-1
9) it is used for finding complex roots of a number
Answer:
9
Step-by-step explanation:
(-9)^1/3 * (-81)^1/3
We can rewrite -81 as 9 * -9
So it can be rewritten as:
(-9)^1/3 * (9*-9)^1/3
Since they are all raised to the 1/3, we can combine the bases:
(-9*9*-9)^1/3 =
(9*9*9)^1/3, because the two negatives turn into a positive:
So this is basically:
(9^3)^1/3 = 9^1 = 9
12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
3(2)-18=-12
6-18 = -12
-12 = -12
