Lia can paint 600 square feet in 2 and a half hours at this rate how many square feet can she paint in 1 hour

Mathematics

1 answer:

lyudmila [28]3 years ago

7 0

The answer would be that she can paint 240 square feet in one hour!

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Function f (x)= 9x+7÷x-1

Andreyy89

I hope this helps you

5 0

4 years ago

I need help only on number 3

DochEvi [55]

Gaps have no data in them. So the range 1-2 is a gap.

Clusters are groups of data that are right next to each other.

So the range 3-6 on your dot plot is a cluster, because there is a group of data there with no gaps.

Peaks are the greatest amount of data in the dot plot. 0 and 5 are the peaks because they both have the most data, 4.

8 0

3 years ago

Help please please please please please<br> 6th & 7th

raketka [301]

First lets start with number six. The only way to solve this is if you determine what "a" and "b" are using the first log they have given to you. $log_a_ba=\frac{1}{3}$

The first variable that I solved for was "a" and $a=e^\frac{in(b)}{2}[tex]{[tex] 0$ }

The same is also true for "b", but when you put both "a" and "b" together the only combination that I have found to work is $a=\frac{1}{2} , b=\frac{1}{4}$

Next you plug these numbers in for "a" and "b" on the second equation to get something that looks like this: $log_\frac{1}{2}_*_\frac{1}{4} (\frac{\sqrt{\frac{1}{2}}}{\sqrt[3]{\frac{1}{4}}} )= -\frac{1}{18}$ and the picture below shows where the answer becomes a negative fraction.

https://www.symbolab.com/solver/logarithms-calculator/%20%5Clog_%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B4%7D%7D%5Cleft(%5Cfrac%7B%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5Cright)

If you paste that link in your search bar it will give you a even more in depth understanding of how to get this answer

Next is #7, the easier of the two.There are two ways to solve for your answers. According to the graph of this equation there are four possible real solutions. $x=2,-2,\sqrt{2}, and -\sqrt{2}$ . (This does not account for any complex solutions)