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blondinia [14]
4 years ago
13

Compare and contrast the effects that a proportional dimension change has on perimeter and area of figures

Mathematics
2 answers:
zloy xaker [14]4 years ago
6 0

Answer with explanation:

1.In terms of Perimeter

For any 2 Dimensional shape, having fixed dimension, (Perimeter is calculated=S), and if the shape is dilated with Dilation factor k,that is the similar shape has the perimeter equal to Dilation factor multiplied by Perimeter of Pre -Image=k S).

If Dilation Factor <1,

Perimeter of  image will be less than Pre image.

If , Dilation Factor >1

Perimeter of Image will be greater than Pre-Image.

Actual Perimeter of Shape = S

Dilation factor or Proportionality Constant = k

New Perimeter of Shape = k*S

2. In terms of Area

Let me explain this concept by taking a four sided Quadrilateral named square.

Suppose, Side of Square = a units

Area of Square = a²

If side is dilated by a factor of m units

Area of new Square obtained = (m a)²= m²a²

Area increases or decreases by m² units, if dilation factor<1,the area Decreases, and if Dilation Factor >1, area increases.

→So, when Shape is Dilated by a factor m ,or you can say constant of proportionality is m,then area of new Shape is (m²,)square of × area of original shape.

Kipish [7]4 years ago
3 0
A proportional dimension will change the perimeter by the factor of itself. And will change the area by the factor of the dilation squared.
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Step-by-step explanation:

To find the average rate of change of a function over a given interval, basically you need to find the slope. The mathematical definition of the slope is very similar to the one we use every day. In mathematics, the slope is the relationship between the vertical and horizontal changes between two points on a surface or a line. In this sense, the slope can be found using the following expression:

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