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Vanyuwa [196]
2 years ago
11

2 to the 3rd power x 4 ÷ 2+ 2

Mathematics
1 answer:
Elena-2011 [213]2 years ago
8 0
The answer is 18

2 to the 3rd power would be 2*2*2 which is 8
8 x 4=32
32/2=16
16+2=18
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Which of the following are solution to the inequality below -4w - 2 < -38
FromTheMoon [43]

Answer:

w > 9

Step-by-step explanation:

Solve the inequality by using inverse operations.

-4w - 2 < -38

-4w < -36

w > 9

Like solving equations, inequalities should be solved using inverse operations. However, unlike equations, when you divide or multiply by a negative the sign changes.

8 0
3 years ago
Please help! How would you find the relative frequency of being female and attending an action movie?
denpristay [2]
Is this a STARR test? 
A. Divide 99 by 250
6 0
3 years ago
Read 2 more answers
What is the interquartile range of this set of data? 15, 19, 20, 25, 31, 38, 41
Irina18 [472]
First, you have to find the median, which is the number in the middle: 25

Then cut the data in half by the median, so your new data sets are
15,29,20
    and 
31,38,41

Now you find the median of both of those sets, which is 29 and 38.

The interquartile range is the difference between the numbers, so 38-29 = 9.
8 0
3 years ago
Max went to the store and bought 22 apples. He bought twice as many red apples as he did green, and he bought one-third many yel
katrin [286]

Let the number of green apples bought be x


Green apples = x

Red apples = 2x

Yellow apples = 1/3 (2x) = 2/3 x


Total = 22 apples

x + 2x + 2/3 x = 22

11/3 x = 22

11x = 66

x = 6


Green apples = x = 6

Red apples = 2x = 2(6) = 12

Yellow apples = 2/3 (2x) = 2/3 (6) = 4


Answer: Green = 6, Red = 12, Yellow = 4

7 0
3 years ago
Please help with this and explain how to do it, I'll give 15 points
MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = \frac{10}{2} = 5 cm

Volume of the outer ball V_{1} = \frac{4}{3}\pi (r)^3

                                         = \frac{4}{3}\pi (5)^3

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball V_{2} = \frac{4}{3}\pi (4)^3

Volume of the metal used in the metallic ball = V_{1}-V_{2}

                                                                           = \frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}

                                                                           = \frac{4}{3}\pi [(5)^3-(4)^3]

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0
3 years ago
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