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2 years ago

2 to the 3rd power x 4 ÷ 2+ 2

Mathematics

1 answer:

Elena-2011 [213]2 years ago

8 0

The answer is 18

2 to the 3rd power would be 2*2*2 which is 8
8 x 4=32
32/2=16
16+2=18

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What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?

DedPeter [7]

f(x) = 112 - kx
f(-3) = 112 - k(-3)
f(-3) = 112 - (-3k)
f(-3) = 112 + 3k
121 = 112 + 3k
- 112 - 112
      9 = 3k
      3    3
      3 = k

6 0

2 years ago

It takes 40 units of maple sap to produce 1 ounce of maple syrup. Jane and her family are bottling maple syrup in 20 -ounce bott

Setler [38]

Answer:

10,800

-1200

Step-by-step explanation:

Given that :

40 units of maple sap = 1 ounce of maple syrup

Using a 20 - ounce bottle, 2 ounces of air is left

Ounces of actual syrup = (20 - 2) = 18 ounces

Number of maple sap required to fill 15 bottles :

Number of maple saps required to fill 18 ounces bottle :

40 units = 1 ounce

x = 18 ounces

Hence, for 18 ounces of maple syrup :

(40 * 18).= 720 units of maple sap

For 15 bottles of 18 ounces maple syrup:

(720 * 15) = 10,800 units of maple sap

If they had filled each bottle to the top:

(40 * 20 * 15) = 12000 units of maple sap

10,800 - 12000 = - 1200 units of maple sap

5 0

3 years ago

4 – (2y + 5) = 3(1 – 4y) show steps please

Lelu [443]

Answer/Step-by-step explanation:

Let's solve your equation step-by-step.

4−(2y+5)=3(1−4y)

Step 1: Simplify both sides of the equation.

4−(2y+5)=3(1−4y)

4+−1(2y+5)=3(1−4y)(Distribute the Negative Sign)

4+−1(2y)+(−1)(5)=3(1−4y)

4+−2y+−5=3(1−4y)

4+−2y+−5=(3)(1)+(3)(−4y)(Distribute)

4+−2y+−5=3+−12y

(−2y)+(4+−5)=−12y+3(Combine Like Terms)

−2y+−1=−12y+3

−2y−1=−12y+3

Step 2: Add 12y to both sides.

−2y−1+12y=−12y+3+12y

10y−1=3

Step 3: Add 1 to both sides.

10y−1+1=3+1

10y=4

Step 4: Divide both sides by 10.

10y

Answer:

y= 2/5

6 0

2 years ago

Read 2 more answers

Solve for x. 2 1/2x−3/4(2x+5)=3/8<br><br> Please hurry

Fofino [41]

Answer:

x= - 1.48 or 0.48

Step-by-step explanation:

I used general formula. Hope I'm on a right path.

8 0

2 years ago

Tires have a normal distribution with a mean of 70000 miles and a standard deviation of 4400 miles. What proportion of tires wil

yarga [219]

Let T = the distance, in miles, a tire lasts

T ~ N(70000,4400<span>²</span>)

P(T $\geq$ 75000)
= P(Z $\geq \frac{75000 - 70000}{4400}$ )
= P(Z $\geq \frac{25}{22}$ )
≈ P(Z $\geq$ 1.14)
= 1 - P(Z < 1.14)
≈ 1 - 0.8729
= 0.1271

5 0

3 years ago