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Talja [164]
3 years ago
5

Decrease £220 by 15%

Mathematics
2 answers:
Natali5045456 [20]3 years ago
8 0
10% = £22
5% = £11

11 + 22 = £33

£220 - £33 = £187
sasho [114]3 years ago
3 0

220, percentage decreased by 15% (percent) of its value = 187
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Please help! Could you answer all!?
Brums [2.3K]

Answer:

1.) 48

2.) 65

3.) 36

Step-by-step explanation:

1.)     If the equation is 6(x-4) and x = 12, then all we have to do is plug in the value of x. When we plug in, all we do is substitute 12 for x because they mentioned in the question that x = 12. So, we end up getting 6(12 - 4). After solving this, we get 48.

2.)     This problem is a lot like the last problem. All we need to do is substitute /plug in the values of x and y into the equation, to get 4(4^2) - 35/7 - (8 + 14). After solving, we get 65.

3.) .     This problem, once again, is also a lot like the last problems. We need to substitute the value of x into the equation 8x+12. Since we know from the problem that x is 3, all we have to do is 8 * 3 + 12.

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3 years ago
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Formula of interior and exteiror angle and how much interior + exterior equals to
VLD [36.1K]

Answer:

The formula for calculating the size of an interior angle is: interior angle of a polygon = sum of interior angles ÷ number of sides. The sum of exterior angles of a polygon is 360°. The formula for calculating the size of an exterior angle is: exterior angle of a polygon = 360 ÷ number of sides.Properties of exterior angles.  The sum of exterior angle and interior angle is equal to 180 degrees.

Step-by-step explanation:

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2 years ago
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AysviL [449]

Answer:

A. March

Step-by-step explanation:

You can tell by subtracting the tallest bar in the month from the shorter one, and seeing which number is bigger out of all of them.

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Mr Smith's art class took a bus trip to an art museum. The bus averaged 65 miles per hour on the highway and 25 miles per hour i
Leya [2.2K]
Let x be the distance traveled on the highway and y the distance traveled in the city, so:
\left \{ {{x+y=375} \atop { \frac{1}{65}x+ \frac{1}{25}y =7}} \right.
 
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\left[\begin{array}{ccc}1&1&\\ \frac{1}{65} & \frac{1}{25} &\end{array}\right]   \left[\begin{array}{ccc}x&\\y&\end{array}\right] =  \left[\begin{array}{ccc}375&\\7&\end{array}\right]

Next, we are going to find the determinant:
D=  \left[\begin{array}{ccc}1&1\\ \frac{1}{65} & \frac{1}{25} \end{array}\right] =(1)( \frac{1}{25}) - (1)( \frac{1}{65} )= \frac{8}{325}
Next, we are going to find the determinant of x:
D_{x} =  \left[\begin{array}{ccc}375&1\\7& \frac{1}{25} \end{array}\right] = (375)( \frac{1}{25} )-(1)(7)=8

Now, we can find x:
x=  \frac{ D_{x} }{D} = \frac{8}{ \frac{8}{325} } =325mi

Now that we know the value of x, we can find y:
y=375-325=50mi

Remember that time equals distance over velocity; therefore, the time on the highway will be:
t_{h} = \frac{325}{65} =5hours
An the time on the city will be:
t_{c} = \frac{50}{25} =2hours

We can conclude that the bus was five hours on the highway and two hours in the city. 

8 0
3 years ago
I dont understand how to simplify an expression with exponents
Mashutka [201]

Answer:

3^4

Step-by-step explanation:

Simplifying an expression with expression with exponents:

If they are dividing, we keep the base and subtract the exponents. For example:

\frac{a^x}{a^y}=a^{x-y}

In this question:

\frac{3^2}{3^{-2}}=3^{2-(-2)}=3^{2+2}=3^4

8 0
1 year ago
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