Answer:
Step-by-step explanation:
Assuming a normal distribution for the amount spent by Canadian households for high-speed broadband access, the formula for normal distribution is expressed as
z = (x - u)/s
Where
x = amount spent by the Canadian households.
u = mean amount spent monthly.
s = standard deviation
From the information given,
u = $80.63 CDN
s = $27.32 CDN
We want to find the probability that the average amount will exceed $85. It is expressed as
P(x greater than 85) = 1 - P(x lesser than or equal to 85)
For x = 85
z = (85 - 80)/27.32 = 0.18
Looking at the normal distribution table, the corresponding z score is 0.57142
P(x greater than 85) = 1 - 0.57142 = 0.43
Answer:
52 X 60 equals 3120, divide that by 100, to get 31.20, and then do 52.00-31.20 to 20.8. plus sales tax, would equal, 20.8 X 6.25% = 1.3. add that onto the original answer to get the final answer, 22.1. Hope this helps! :)
We are given:
There seems to be nothing I can do to simplify this equation. However, I can factor out an 
since they both have at least an . Here is what we get:
This is in the simplest form I can get into. I cannot do anything more to simplify this expression. This is your final answer.
