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kykrilka [37]
3 years ago
13

Help pls do allll 6 questions... with steps

Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0
You just want to simplify right?!

45. (a^2b^3)(ab)^-2
= (a^2b^3)(a^-2b^-2)
= b
46. (-3x^3y)^2(4xy^2)
= (-9x^6y^2)(4xy^2)
= -36x^7y^4
47. 3c^2d(2c^3d^5) / 15c^4d^2
= 6c^5d^6 / 15c^4d^2
= 2/5c1/4x^4
48. -10g^6h^9(g^2h^3) / 30g^3h^3
= -10g^8h^12 / 30g^3h^3
= -1/3g^5h^9
49. 5x^4y^2(2x^5y^6) / 20x^3y^5
= 10x^9y^8 / 20x^3y^5
= 1/2x^6 1/3y^3
50. -12n^7p^5(n^2p^4) / 36n^6p^7
= -12n^9p^9 / 36n^6p^7
= -1/3n^3p^2

(Sorry it’s messy it’d look better if my phone could actually put the numbers to the power)
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Answer:

m\angle ECB+m\angle EFB=180

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m\angle CDB+m\angle DCB+m\angle CBD=180 \degree

Step-by-step explanation:

From the diagram, quadrilateral BCEF is a cyclic quadrilateral.

Opposite angles if a cyclic quadrilateral sum up to 180°

m\angle ECB+m\angle EFB=180

The diagonals intersect at D to form two pairs of vertical angles, and vertical angles are congruent.

m\angle CDB\cong m\angle EDF

Also sum of angles in triangle CBD is 180°.

m\angle CDB+m\angle DCB+m\angle CBD=180 \degree

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3 years ago
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3 years ago
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Answer:

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