Answer:
depending on the form of how your question is actually written .. The answer will either be :
x= -1
or
There are no values of x that make the equation true. No solution.
Step-by-step explanation:
Hope this helps
Answer: 8/9 is rational
.2593 irrational
square root of 7: irrational
square root of .25 is rational
square root of 14: irrational
0 is a: rational
square root of 280: irrational
square root of 35: is irrational
.2222: is rational
square root of 3r is a rational number......
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
Standard form is written in the order of the exponent <em>on</em><em> </em><em>a</em><em> </em><em>variable</em> from highest to lowest.
#1 exponents go 2, 1 , then zero. So, this is standard form.
#2 exponents go 2 then zero, so this is standard form.
#3 exponents go 1 then 2 then zero, so this is <em><u>not</u></em> in standard form.
#4 exponents go 3 to 2 to 1, so this is still in standard form.
hope this helps!
It would be 24.6 ×24.6
it's 605.16
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60